Answer:
current = 2.67 A
Explanation:
we have given,
Q(t) = t³− 2t² + 4t + 1
to find I at t = 0.7s
we know
so,
current at t= 0.7s
I = 2.67 A
hence, current comes out to be 2.67 A
Without power you can't work .
Answer:
a) u = 6 m/s
b) a = 4 m/s²
c) d(3) = 16 m
Explanation:
equation for the first second
distance will be the average velocity times the time of travel
8 = ½(u + (u + at))t t is one second, so reduces to
8 = u + ½a
velocity at the end of the first second is
v = u + at = u + a
position equation for the second period is
12 = ½((u + a) + (u + a + at))t t is one second so reduces to
12 = u + 3a/2
subtracting the first position equation from the second
12 - 8 = u + 3a/2 - (u + ½a)
a = 4 m/s²
8 = u + ½4
u = 6 m/s
in the third second
d = 6(3) + ½(4)(3²) - 8 - 12
d = 16 m
Answer: a) Cnew=Cinitial ; b) λouter new= 2*λ outer initial
Explanation: In order to explain this question we have to take into account the expression of teh cylinder capacitor given by:
C/L= (2*π*εo)/ln (b/a)= where b and a are the outer and inner radius, respectively. L is the length of the capacitor.
As you can se this formule depents of geometrical characateristics of the capacitor.
The capacitance is the same after change the densities of charge.
On the other hand,
The new charge in each cylinder ( inner and outer) is determined
The new potential is 2 times the initial one so
V new= 2* Vinitial
Also we know that
Vnew= Q/C= λnew*L/C; C= constant
using this formule and considering that V new is doubled then the charge per one meter length, is also doubled .
This is as follow:
Vnew= λnew*L/C=
λnew = (2*Vinitial)* C/L= 2 (λ initial)
Then λouter new = 2* λouter initial
Answer:
Option (a)
Explanation:
Given that,
Mass of a car, m = 1200 kg
Force exerted by the engine, F = 600 N
Noe force,F = ma
a is the acceleration of the engine
So, the acceleration of the car is 0.5 m/s².