Question

A vertically polarized light wave of intensity 1000 mW/m2 is coming toward you, out of the screen. After passing through this polarizing filter, the wave's intensity is

Answer 1

Answer:

The intensity is $I = 500 mW/m^2$

Explanation:

From the question we are told that

    The  intensity of the unpolarized light is $I_o = 1000 \ m W /m^2 = 1000 *10^{-3} \ W/m^2$

Generally the intensity of the light emerging from the polarizer is  mathematically represented as

          $I = \frac{I_o}{2}$

substituting values

         $I = \frac{1000 *10^{-3}}{2}$

         $I = 500 *10^{-3} W/m^2$

         $I = 500 mW/m^2$