Answer:
the volume of the gas will be 1/8 of the original value
Explanation:
Answer: 3.52 grams
Explanation:

Given moles:
moles of oxygen = 6.62
moles of 
According to stoichiometry:
2 moles of benzene reacts with = 15 moles of oxygen
Thus 0.08 moles of benzene will react with =
moles of oxygen
Thus benzene is the limiting reagent as it limits the formation of products and oxygen is the excess reagent.
As 2 moles of benzene produce = 12 moles of carbon dioxide
0.08 mole of benzene will produce =
of carbon dioxide
Mass of carbon dioxide=
Thus 3.52 g of carbon dioxide are produced.
The rate of reaction between oxygen and copper is higher at high temperature. The rate of reaction between oxygen and copper is lower at room temperature.
at high temperature copper penny will react with oxygen as shown below

The reaction does not occur easily at room temperature
We can say that the reaction between copper and oxygen is an endothermic reaction so the rate of reaction is high at high temperature.
The bond energy of oxygen molecules need energy to react with copper and form copper oxide.
Ka x Kb = Kw Kw = 1 x 10⁻¹⁴
(1.3 x 10⁻⁷) x Kb = 1 x 10⁻¹⁴
Kb = ( 1 x 10⁻¹⁴ ) / ( 1.3 x 10⁻⁷)
Kb = 7.7 x 10⁻⁸
Answer D
hope this helps!