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soldier1979 [14.2K]
3 years ago
5

Adita lifts a book from the floor, carries it across the room, and places it on a high shelf. When is Adita doing work on the bo

ok?
She does work on the book at no time during this process.
She does work only while she carries the book across the room.
She does work from the moment she touches the book until she lets it go.
She does work as she picks up the book and as she lifts it to the shelf.
Physics
2 answers:
noname [10]3 years ago
5 0

She does work from the moment she touches the book until she lets it go. Work is anything that requires energy. Therefore, she is working as she picks up the book, carries it, and when she is lifting it onto the shelf.

ZanzabumX [31]3 years ago
3 0

option d

took test on edu

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Answer:

<em>a. The frequency with which the waves strike the hill is 242.61 Hz</em>

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Explanation:

Part A

The car is the source of our sound, and the frequency of the sound wave it emits is given as 231 Hz. The speed of sound given can be used to determine the other frequencies, as expressed below;

f_{1} = f[\frac{v_{s} }{v_{s} -v} ] ..............................1

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v = 36.4 mph *\frac{1609 m}{1 mile} *\frac{1 hr}{3600 secs}

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f_{1}  = 242.61 Hz.

Therefore, the frequency which the wave strikes the hill is 242.61 Hz.

Part B

At this point, the hill is the stationary point while the driver is the observer moving towards the hill that is stationary. The frequency of the sound waves reflecting the driver can be obtained using equation 2;

f_{2} = f_{1} [\frac{v_{s}+v }{v_{s} } ]

where f_{2} is the frequency of the reflected sound;

f_{1}  is the frequency which the wave strikes the hill = 242.61 Hz;

v_{s} is the speed of sound = 340 m/s;

v is the speed of the car = 16.27 m/s.

Substituting our values into equation 1 we have;

f_{2} = 242.61 Hz [\frac{340 m/s+16.27 m/s }{340 m/s } ]

f_{2}  = 254.23 Hz.

Therefore, the frequency of the reflected sound is 254.23 Hz.

Part C

The beat frequency is the change in frequency between the frequency of the direct sound  and the reflected sound. This can be obtained as follows;

Δf = f_{2} -  f_{1}  

The parameters as specified in Part A and B;

Δf = 254.23 Hz - 242.61 Hz

Δf  = 11.62 Hz

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