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ikadub [295]
3 years ago
7

The electron in a hydrogen atom can undergo a transition from n = 4 to n = 3, emitting a photon with energy 1.06 × 10 –19J. Use

this transition to answer the following questions.
i. What is the wavelength of this transition?
ii. How does this transition show that the position of the electron is quantized?
Chemistry
1 answer:
konstantin123 [22]3 years ago
5 0

Answer:

Wavelength (λ) = 1.875 × 10⁻⁶ m

Explanation:

Given:

Energy (e) =  1.06 × 10⁻¹⁹ J

Find:

Wavelength (λ) = ?

Computation:

e = hc / λ

λ = hc / e

where c = 3 × 10⁸

Planck's constant (h) = 6.625 × 10⁻³⁴

So,

Wavelength (λ) = (6.625 × 10⁻³⁴)(3 × 10⁸) / (1.06 × 10⁻¹⁹)

1. Wavelength (λ) = 1.875 × 10⁻⁶ m

2. Given n = 4 to n = 3 both are integer not fraction so, electron is quantize

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2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4
agasfer [191]

Answer:

d=4.24x10^{-4}\frac{lb}{in^3}

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

d=\frac{m}{V}

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

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Now, we proceed to the conversion to lb/in³ by using the following setup:

d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}

Regards!

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