Answer:
9.96x10^-20 kg-m/s
Explanation:
Momentum p is the product of mass and velocity, i.e
P = mv
Alpha particles, like helium nuclei, have a net spin of zero. Due to the mechanism of their production in standard alpha radioactive decay, alpha particles generally have a kinetic energy of about 5 MeV, and a velocity in the vicinity of 5% the speed of light.
From this we calculate the speed as
v = 5% 0f 3x10^8 m/s (speed of light)
v = 1.5x10^7 m/s
The mass of an alpha particle is approximately 6.64×10−27 kg
Therefore,
P = 1.5x10^7 x 6.64×10^−27
P = 9.96x10^-20 kg-m/s
Answer:
Explanation:
Given
mass of crane 
distance moved 
Since it is moving with a constant velocity therefore net force on it is zero
Tension force=weight
T=mg
Work done by Tension T is
Work done by Gravity will be equal in magnitude but opposite in sign and can be obtained by work energy theorem which states that change in kinetic energy of object is equal to work done by all the forces
The answer to this question is false
Answer:
Direction
Explanation:
There are two types of electric current:
- DC (Direct current): in a direct current, the direction of the flow of the current is constant; this means that it does not change. This means that the potential difference supplied has always the same direction, so that the electrons travel always in the same direction through the circuit
- AC (Alternating current): in an alternating current, the direction of the flow of the current is constantly reverses. This means that the direction of the potential difference supplied constantly changes, therefore the electrons travel half the time in one direction and half the time in the opposite direction.
Answer:
<em>Fx = 121.24lb</em>
<em>F = 140lb</em>
Explanation:
Since we are not given the angles subtended by the force, we can assume it to be 30 degrees.
The y component of the force expressed by the formula:
Fy = Fsintheta
Given the y-component of the force F to bee 70lb
70lb = Fsintheta
Get magnitude of the force
F = 70/sin theta
F = 70/sin 30
F = 70/0.5
F = 140lb
Get the x-component of the force
Fx = Fcos theta
Fx = 140cos 30
Fx = 140(0.8660)
Fx = 1,212.4lb
<em>Hence the x-component of the force sis 121.24lb</em>
<em></em>
<em>Note that the angle used was assumed. Other values can as well be used</em>
