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3 years ago

Which of Hubble's findings supported the big bang theory? Check all that apply.

Chemistry

2 answers:

Stella [2.4K]3 years ago

8 0

Answer:

C,D,E

Explanation:

JUST TOOK THE TEST

grigory [225]3 years ago

3 0

<u>Out of all given options, Hubble's findings supported the big bang theory are as follows: </u>

The universe formed from a central point.
Most galaxies in the universe are moving away from Earth.
There are billions of galaxies in the universe, not just one.

Option C, D, and E

<u>Explanation: </u>

According to big bang theory, the universe is increasing its region of occupancy in free space. As it is known that the universe is composed of several galaxies. So this spreading of the universe is nothing but spreading of galaxies.

And this is confirmed from Hubble’s findings using Hubble’s telescope. As they have observed that the speed at which the galaxies are travelling in free space has been increased at a faster rate.

So, the galaxies are used to move away from Earth with time at a faster rate which confirms the big bang theory of universe formation. Also, in simple words, universe started from big bang according to cosmology' standard theory, it’s just moves from everything else.

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Explanation:

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3 years ago

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3 years ago

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Answer:

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Explanation:

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3 years ago

A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooli

Diano4ka-milaya [45]

Answer:

$\large \boxed{109.17 \, ^{\circ}\text{C}}$

Explanation:

Data:

50/50 ethylene glycol (EG):water

V = 4.70 gal

ρ(EG) = 1.11 g/mL

ρ(water) = 0.988 g/mL

Calculations:

The formula for the boiling point elevation ΔTb is

$\Delta T_{b} = iK_{b}b$

i is the van’t Hoff factor — the number of moles of particles you get from 1 mol of solute. For EG, i = 1.

1. Moles of EG

$\rm n = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{1000 mL}}{\text{1 L}} \times \dfrac{\text{1.11 g}}{\text{1 mL}} \times \dfrac{\text{1 mol}}{\text{62.07 g}} = \text{159 mol}$

2. Kilograms of water

$m = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{998 g}}{\text{1 L}} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{8.88 kg}$

3. Molal concentration of EG

$b = \dfrac{\text{159 mol}}{\text{8.88 kg}} = \text{17.9 mol/kg}$

4. Increase in boiling point

$\rm \Delta T_{b} = iK_{b}b = 1 \times 0.512 \, \, ^{\circ}\text{C} \cdot kg \cdot mol^{-1} \, \times 17.9 \cdot mol \cdot kg^{-1} = 9.17 \, ^{\circ}\text{C}$

5. Boiling point

$\rm T_{b} = T_{b}^{\circ} + \Delta T_{b} = 100.00 \, ^{\circ}\text{C} + 9.17 \, ^{\circ}\text{C} = \mathbf{109.17 \, ^{\circ}C}\\\rm \text{The boiling point of the solution is $\large \boxed{\mathbf{109.17 \, ^{\circ}C}}$}$

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3 years ago

Which one is a decomposition reaction?

vodomira [7]

Answer:

b no

Explanation:

because it is decomposing into two elements

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3 years ago

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