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2 years ago

Which of Hubble's findings supported the big bang theory? Check all that apply.

Chemistry

2 answers:

Stella [2.4K]2 years ago

8 0

Answer:

C,D,E

Explanation:

JUST TOOK THE TEST

grigory [225]2 years ago

3 0

<u>Out of all given options, Hubble's findings supported the big bang theory are as follows: </u>

The universe formed from a central point.
Most galaxies in the universe are moving away from Earth.
There are billions of galaxies in the universe, not just one.

Option C, D, and E

<u>Explanation: </u>

According to big bang theory, the universe is increasing its region of occupancy in free space. As it is known that the universe is composed of several galaxies. So this spreading of the universe is nothing but spreading of galaxies.

And this is confirmed from Hubble’s findings using Hubble’s telescope. As they have observed that the speed at which the galaxies are travelling in free space has been increased at a faster rate.

So, the galaxies are used to move away from Earth with time at a faster rate which confirms the big bang theory of universe formation. Also, in simple words, universe started from big bang according to cosmology' standard theory, it’s just moves from everything else.

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Which of the following atoms would have the longest de Broglie wavelength, if all have the same velocity?

GenaCL600 [577]

Answer:

Explanation:

The phenomenon of wave particle duality was well established by Louis deBroglie. The wavelength associated with matter waves was related to its mass and velocity as shown below;

λ= h/mv

Where;

λ= wavelength of matter waves

m= mass of the particle

v= velocity of the particle

This implies that if the velocities of all particles are the same, the wavelength of matter waves will now depend on the mass of the particle. Hence; the wavelength of a matter wave associated with a particle is inversely proportional to the magnitude of the particle's linear momentum. The longest wavelength will then be obtained from the smallest mass of matter. Hence lithium which has the smallest mass will exhibit the longest DeBroglie wavelength

4 0

3 years ago

The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?

Vedmedyk [2.9K]

Answer : The volume of pure diamond is $0.493inch^3$

Explanation : Given,

Density of pure carbon in diamond = $3.52g/cm^3$

Moles of pure diamond = 23.7 moles

Molar mass of carbon = 12 g/mol

First we have to calculate the mass of carbon or pure diamond.

$\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}$

Molar mass of carbon = 12 g/mol

$\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g$

Now we have to calculate the volume of carbon or pure diamond.

Formula used:

$Density=\frac{Mass}{Volume}$

Now putting all the given values in this formula, we get:

$3.52g/cm^3=\frac{284.4g}{Volume}$

Volume = $80.8cm^3$

As we know that:

$1cm^3=0.061inch^3$

So,

Volume = $0.061\times 80.8inch^3$

Volume = $0.493inch^3$

Therefore, the volume of pure diamond is $0.493inch^3$

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2 years ago

What happens when you add acetic acid vinegar and sodium bicarbonate baking soda nahco

Sophie [7]

Explanation:

oh shi sorry I wish I could help but I'm stupid

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2 years ago

a compound has an empirical formula of CH2 what is the molecular formula if it's molar mass is 252.5 grams/mol

Goryan [66]

Empirical formula is the simplest ratio of components making up the compound. the molecular formula is the actual ratio of components making up the compound.

the empirical formula is CH₂. We can find the mass of CH₂ one empirical unit and have to then find the number of empirical units in the molecular formula.

Mass of one empirical unit - CH₂ - 12 g/mol x 1 + 1 g/mol x 2 = 12 = 14 g

Molar mass of the compound is - 252 .5 g/mol

number of empirical units = molar mass / mass of empirical unit

= $\frac{252.5 g/mol}{14 g}$

= 18 units

Therefore molecular formula is - 18 times the empirical formula

molecular formula - CH₂ x 18 = C₁₈H₃₆

molecular formula is C₁₈H₃₆

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3 years ago

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Talja [164]

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3 years ago

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