<u>Answer:</u> 2.00 atm
<u>Explanation:</u>
The gas is kept under the same temperature in this problem. Assuming the amount of gas is constant, we can apply the Boyle's law.
The Boyle's law equation,
P₁V₁ = P₂V ₂
Plug in the values,
1.00 atm x 4.0 L = P₂ x 2.0 L
Simplify,
4.00 atm L = 2 P₂ L
Now flip the equation,
2 P₂ L = 4.00 atm L
Dividing both sides by 2 we get,
P₂ = 2.00 atm
Answer:
- 130.64°C.
Explanation:
- We can use the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have two different values of V and T:
<em>V₁T₂ = V₂T₁</em>
<em></em>
V₁ = 634.0 L, T₁ = 21.0°C + 273 = 294.0 K.
V₂ = 307.0 L, T₂ = ??? K.
<em>∴ T₂ = V₂T₁/V₁ </em>= (307.0 L)(294.0 K)/(634.0 L) = <em>142.36 K.</em>
<em>∴ T₂(°C) = 142.36 K - 273 = - 130.64°C.</em>
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