Explanation:
Natural length of a spring is . The spring is streched by . The resultant energy of the spring is .
The potential energy of an ideal spring with spring constant and elongation is given by .
So, in the current problem, the natural length of the spring is not required to find the spring constant .
∴ The spring constant of the spring =
Answer:
R (120) = 940Ω
Explanation:
The variation in resistance with temperature is linear in metals
ΔR (T) = R₀ α ΔT
where α is the coefficient of variation of resistance with temperature, in this case α = -0,0005 / ºC
let's calculate
ΔR = 1000 (-0,0005) (120-0)
ΔR = -60
Ω
ΔR = R (120) + R (0) = -60
R (120) = -60 + R (0)
R (120) = -60 + 1000
R (120) = 940Ω
I believe it would be weight. mass never changes.
Answer:
To know the time ,length area
Answer:
a
Explanation:
what the heck is a medium