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3 years ago

How much energy ( in joules ) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature ?

Physics

2 answers:

aleksley [76]3 years ago

5 0

Answer:

B. 17,705.1 J

Explanation:

The hear released when the mercury condenses into a liquid is given by:

$Q=m \lambda_v$

where

m = 0.06 kg is the mass of the mercury

$\lambda_v$ is the latent heat of vaporization

For mercury, the latent heat of vaporization is $\lambda_v = 296 kJ/kg$ , so the heat released during the process is:

$Q=(0.06 kg)(296 kJ/kg)=17.76 kJ = 17,760 J$

So, the closest option is

B. 17,705.1 J

valina [46]3 years ago

5 0

The energy ( in joules ) released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature is about 697.08 J. in other to solve this problem, should know the latent heat of fusion of mercury which is equal to about 11.4 kJ/kg and multiplying by mass of mercury.

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Analyze the following terms and phrases about solar activity. Select the two that represent correct matches between cause and ef

blagie [28]

Answer:

a) solar activity -- sudden eruptions of large bubbles of plasma and magnetic energy

and

d) solar flare -- sudden release of magnetic energy

Explanation:

We can start by eliminating the options that are definitely wrong.

A coronal mass ejection is not a relatively cool spot on surface of the sun, in fact such a spot is a sunspot, while a coronal mass ejection occurs when the magnetic field of the sun emerges as a loop. Thus, both options B and E are incorrect, leaving only A, C, and D. Option C makes no sense, as the sun's gravitational field does not 'churn'. Thus, only options A and D are left. A closer look at A and D reveals they are correct; solar flares are in fact sudden releases of magnetic energy, as seen in this quote from UC Berkeley's website; "Solar flares are caused by sudden changes of strong magnetic fields in the Sun's corona.". And solar activity is a blanket term for the effects of eruptions of plasma and magnetic energy from the sun.

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3 years ago

Que es un kilogramo fuerza.?

Kipish [7]

El kilogramo de fuerza, o kilopond, es una unidad de fuerza métrica gravitacional. Es igual a la magnitud de la fuerza ejercida sobre un kilogramo de masa en un campo gravitatorio de 9.80665 m / s².

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3 years ago

What is the order of magnitude of the distance of Sun to nearest star in meters?

neonofarm [45]

Answer:

Approximating the Milky Way as a disk and using the density in the solar neighborhood, there are about 100 billion stars in the Milky Way.

Explanation:

Since we are making an order of magnitude estimate, we will make a series of simplifying assumptions to get an answer that is roughly right.

Let's model the Milky Way galaxy as a disk.

The volume of a disk is:

⋅

Plugging in our numbers (and assuming that

≈

)

⋅

(

)

⋅

(

)

Is the approximate volume of the Milky Way.

Now, all we need to do is find how many stars per cubic meter (

) are in the Milky Way and we can find the total number of stars.

Let's look at the neighborhood around the Sun. We know that in a sphere with a radius of

m there is exactly one star (the Sun), after that you hit other stars. We can use that to estimate a rough density for the Milky Way.

Using the volume of a sphere

(

)

256

−

stars /

Going back to the density equation:

Plugging in the density of the solar neighborhood and the volume of the Milky Way:

(

256

−

)

⋅

(

)

256

stars (or 100 billion stars)

Is this reasonable? Other estimates say that there are are 100-400 billion stars in the Milky Way. This is exactly what we found.

4 0

2 years ago

Read 2 more answers

Which characteristic would you expect from a sample with a pH of 9

Verizon [17]

I would expect it to be slightly basic.

7 0

3 years ago

A(n) 83 kg fisherman jumps from a dock into a 139 kg rowboat at rest on the West side of the dock. If the velocity of the fisher

Anna71 [15]

here we can say that there is no external force on fisherman and dock

so here we will use momentum conservation theory

As per momentum conservation

initial momentum of fisherman + boat = final momentum of fisherman + boat

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

now we will have

$83(3.1) + 139(0) = 83 v + 139 v$

$257.3 = 222v$

$v = 1.16 m/s$

so the speed of boat and fisherman will be 1.16 m/s

3 0

3 years ago