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shusha [124]
3 years ago
8

When creating a graph, why is appropriate title for a graph important?

Chemistry
2 answers:
OleMash [197]3 years ago
6 0

To let you know what you are working with. if you have a wrong name for a graph then you will get the wrong answer
masha68 [24]3 years ago
6 0

Answer;

-To provide an overview of the information the graph contains and also give an indication of the data being looked at.

Explanation;

- It is important to title graphs carefully so the information makes sense and the graph is easy to read and understand.

-The general title of a graph should provide an overview of the information it contains and give the readers an indication of the data they will be looking at.

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Bao + ........ --> BaCO3 + ......
scoray [572]

Explanation:

Bao + .....Co2... --> BaCO3 + ......

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3 years ago
What is chemical potential energy?
tigry1 [53]

Chemical potential energy: chemical potential of a species is energy that can be absorbed or released due to a change of the particle number of the given species, in a chemical reaction or phase transition

Gasoline used as kinetic energy: the various chemicals that make up gasoline contain a large amount of chemical potential energy that is released when the gasoline is burned in a controlled way in the engine of the car. The release of that energy does two things. Some of the potential energy is transformed into work, which is used to move the car

Dynamite used as kinetic energy: the dynamite being used was most likely made of nitroglycerin. Once the dynamite explodes from a percussion force (then breaking of weak bonds to releasing the raw atom) the energy is then converted to thermal, kinetic, and sound energy.

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3 years ago
A 15.0 ml sample of gas at 10.0 degree Celsius and 760 torr changes to a pressure of 1252 torr at 35.0 degree Celsius. What is t
netineya [11]

Answer:

9.91 mL

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (torr)

P2 = final pressure (torr)

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 15.0mL

V2 = ?

P1 = 760 torr

P2 = 1252 torr

T1 = 10°C = 10 + 273 = 283K

T2 = 35°C = 35 + 273 = 308K

Using P1V1/T1 = P2V2/T2

760 × 15/283 = 1252 × V2/308

11400/283 = 1252V2/308

Cross multiply

11400 × 308 = 283 × 1252V2

3511200 = 354316V2

V2 = 3511200 ÷ 354316

V2 = 9.91 mL

4 0
3 years ago
I'm redoing the Heat of Combustion Lab for a better grade and I REALLY need the answers and work for all questions! PLEASE!
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Answer:

Hi, what are the problems on the lab?

Explanation:

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3 years ago
NaOH is typically standardized using potassium hydrogen phthalate (KHP).
DaniilM [7]

Answer:

Na(OH)²

Explanation:

We look for the charges in the periodic table

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2 years ago
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