Acceleration........................................
Answer:
q = 0.036 C
Explanation:
Given that,
Current passes through a defibrillator, I = 18 A
Time, t = 2 ms
We need to find the charge moved during this time. We know that,
Electric current = charge/time

Put all the values,

So, 0.036 C of charge moves during this time.
<span>It's close to the sun without much atmosphere, so it's characterized by </span><span>very extreme temperatures.
Happy studying ^_^</span>