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Furkat [3]
3 years ago
13

Salt is dissolved in a flask of tap water. Distilling the mixture causes the salt to separate from the water. Which type of ener

gy is required to begin the distilling process?
A.
chemical energy
B.
electrical energy
C.
mechanical energy (motion)
D.
thermal energy
Physics
2 answers:
Rasek [7]3 years ago
7 0

Answer:

Thermal energy

Explanation:

olchik [2.2K]3 years ago
4 0

Answer:

thermal energy

Explanation:

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1.- Se desea elevar un cuerpo de 1500kg utilizando una elevadora hidráulica de plato grande
kvv77 [185]

Answer:

181.48 N

Explanation:

Calculate the area :

Area = pi * r² ;

pi = 3.14 ; r1 = 90cm /100 = 0.9m ; r2 = 10/100 = 0.1m

Area 1, A1 = 3.14 * 0.1² = 0.0314 m²

Area 2, A2 = 3.14 * 0.9² = 2.5434 m²

Force, F = mass * acceleration due to gravity

F2 = 1500 * 9.8 = 14700 N

Force 1 / Area 1 = Force 2 / Area 2

Force 1 = (Force 2 / Area 2), * Area 1

Force 1 = (14700 / 2.5434) * 0.0314

Force = 5779.6650 * 0.0314

= 181.48 N

5 0
3 years ago
If heat is gained from a source, it is __________ from the source.
Strike441 [17]

Answer:

Derived, or expended

4 0
2 years ago
What is the numerical value of the slope of the line (without units)?<br>0.083<br>24<br>8.3<br>12
tankabanditka [31]
As close as I can read it, it appears to be

                 1/12  gram/second

           (0.08333... gm/sec)
4 0
3 years ago
There are infinite black and white dots on a plane. Prove that the distance between one black dot and one white dot is one unit.
OlgaM077 [116]

Answer:this is confusing and what subject is this

Explanation:

6 0
3 years ago
Read 2 more answers
The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of
motikmotik

Explanation:

It is given that, the force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the car's speed such that,

F\propto \dfrac{mgv^2}{r}

F=\dfrac{kmgv^2}{r}

mg is the weight of the car

r is the radius of the curve

v is the speed of the car

Case 1.

F = 640 pounds

Weight of the car, W = mg = 2600 pound

Radius of the curve, r = 650 ft

Speed of the car, v = 40 mph

640=\dfrac{k(2600)(40)^2}{650}

k = 0.1

Case 2.

Radius of the curve, r = 750 ft

Speed of the car, v = 30 mph

F=\dfrac{0.1\times 2600\times (30)^2}{750}

F = 312 N

Hence, this is the required solution.

6 0
3 years ago
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