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2 years ago

Calculate the velocity of a car that travelled 120km in 2 hours

Physics

1 answer:

Naddik [55]2 years ago

5 0

I need context poggg

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2 years ago

A 13.0 kg wheel, essentially a thin hoop with radius 1.80 m, is rotating at 469 rev/min. It must be brought to a stop in 16.0 s.

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Answer:

Explanation:

Given

mass of wheel m=13 kg

radius of wheel=1.8 m

N=469 rev/min

$\omega =\frac{2\pi \times 469}{60}=49.11 rad/s$

t=16 s

Angular deceleration in 16 s

$\omega =\omega _0+\alpha \cdot t$

$\alpha =\frac{\omega }{t}=\frac{49.11}{16}=3.069 rad/s^2$

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Change in kinetic energy =Work done

Change in kinetic Energy $=\frac{I\omega ^2}{2}-\frac{I\omega _0^2}{2}$

$\Delta KE=\frac{42.12\times 49.11^2}{2}=50,792.34 J$

(a)Work done =50.79 kJ

(b)Average Power

$P_{avg}=\frac{E}{t}=\frac{50.792}{16}=3.174 kW$

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3 years ago

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3 years ago

Which of these terms means an object's resistance to changing its motion?

Mila [183]

Answer:

Inertia

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All of the above

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2 years ago

What weather does a occluded front bring?

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3 years ago

Calculate the velocity of a car that travelled 120km in 2 hours​

Calculate the velocity of a car that travelled 120km in 2 hours