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VashaNatasha [74]
3 years ago
14

Help please really fast!!

Engineering
1 answer:
ra1l [238]3 years ago
6 0

Answer:368 hdhtygtÿ

901 vuiøöńč

Explanation:

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Wet steam at 15 bar is throttled adiabatically in a steady-flow process to 2 bar. The resulting stream has a temperature of 130°
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\Delta s = 0.8708\,\frac{kJ}{kg\cdot K}

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State 2 - Outlet (Superheated Vapor)

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The change of entropy of the steam is derived of the Second Law of Thermodynamics:

\Delta s = 7.1776\,\frac{kJ}{kg\cdot K} - 6.3068\, \frac{kJ}{kg\cdot K}

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