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3 years ago

Within a particular compound, an atom gives up two electrons. This atom is

Chemistry

2 answers:

ValentinkaMS [17]3 years ago

6 0

Answer:

The correct answer is option B. positively charged.

Explanation:

A positively charged ion is an atom that readily loses its one or more electrons in a compound. Positively charged ion generally has same number of electrons and protons which means they are neutral charge atom. These atoms are generally attracted to negatively charged ion that lack electron in outer shell.

Thus, the correct answer is option. B. positively charged.

lys-0071 [83]3 years ago

3 0

It is a positively charges because when an atom gives up electrons it becomes positively charges. Think of it like this.....its being generous so it deserves to be a positive person. ;D.
It cant be A. because a covalent bond only shares and doesn't give up electrons. Our answer must be an ion.
Its not negatively charged because it didn't gain any.

So our answer is B. positively charged
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A fossil was analyzed and determined to have a carbon-14 level that is 70 % that of living organisms. The half-life of C-14 is 5

Citrus2011 [14]

Answer: 2948

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{5730}=1.21\times 10^{-4}years^{-1}$

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}years^{-1}$

t = age of sample = ?

a = let initial amount of the reactant = 100

a - x = amount left after decay process = $\frac{70}{100}\times 100=70$

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{100}{70}$

$t=2948years$

Thus the fossil is 2948 years old.

5 0

3 years ago

A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.

MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

Density in g/l = 1.020 g/ml * 1000ml/1 l

= 1020 g/l

Mass of solution in 1 l of solution = 1020 g

Mass of solution = mass of solvent + mass of solute

Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

Density of sucrose = mass/volume

= molar mass/molar concentration

= 342.296 * 0.25

= 85.6 g/l

Number of moles = mass/molar mass

= 85.6/342.296

= 0.25 mol

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

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3 years ago

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labwork [276]

Answer:

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3 years ago

the copper anode is weighed before and after the electrolysis reation. if the copper anode is not completely dry when it is weig

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Answer:

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3 years ago

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abruzzese [7]

Answer:

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Explanation:

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