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xenn [34]
4 years ago
6

George created an advertisement for a retail store that sold clothes. He added a discount in the form of a coupon that the custo

mers had to redeem at the store within the next week. Which advertising feature did George use in his advertisement?
Physics
1 answer:
likoan [24]4 years ago
7 0

Answer:

The advertisement feature that George can use is a coupon booklet  with the local newspaper for delivery

Explanation:

George focus on promotion rather than using the other stores strategy of word-of-mouth. Different types of promotion: advertising, public relations, direct selling and sales promotions.A temporary reduction in the price, such as 50% off. Reduction amount  may be a percentage that can be marked on the package.A coupon booklet is inserted into the local newspaper for delivery. Also on checkout  the customer can be given a coupon based on products purchased. The consumer is automatically entered into the contest/event by purchasing the product.

Displays:-

A board on which messages are written in crayon.

Consumers get one sample for free, after their trial and then could decide whether to buy or not

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An object is pushed with a force of 50 Newtons and accelerates at 25 m/s2 . What is the object’s mass?
alekssr [168]

Answer: 2kg

Explanation:

Formula: F=m*a

Where;

F = force

m = mass

a = acceleration

Solve for m;

m=\frac{F}{a}

m=\frac{50N}{25m/s^2}

m=2kg

7 0
4 years ago
Particle moves in a circle of radius 90m with a constant speed 25m/s. how many revolution does it make in 30sec​
Serggg [28]

Answer:

<em>n =1.33 revolutions</em>

Explanation:

<u>Uniform Circular Motion</u>

The angular speed can be calculated in two different ways:

\displaystyle \omega=\frac{v}{r}

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

\omega=2\pi f

Where:

f = frequency

Solving for f:

\displaystyle f=\frac{\omega}{2\pi}

Since the frequency is calculated when the number of revolutions n and the time t are known:

\displaystyle f=\frac{n}{t}

We can solve for n:

n=f.t

The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:

\displaystyle \omega=\frac{25}{90}

\displaystyle \omega=0.278\ rad/s

Now we calculate f:

\displaystyle f=\frac{0.278}{2\pi}

f=0.04421\ Hz

Calculating the number of revolutions:

n = 0.04421*30

n =1.33 revolutions

8 0
3 years ago
Which of the following situations is an example of kinetic energy being transformed into potential energy? Throwing a ball high
motikmotik

Answer: holding the ball in the air without moving it

Explanation:

When the ball goes up it’s potential energy

6 0
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How long would a circuit be connected to produce a current of 0.65 A with a charge of 380 C?
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Answer:

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