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xenn [34]
3 years ago
6

George created an advertisement for a retail store that sold clothes. He added a discount in the form of a coupon that the custo

mers had to redeem at the store within the next week. Which advertising feature did George use in his advertisement?
Physics
1 answer:
likoan [24]3 years ago
7 0

Answer:

The advertisement feature that George can use is a coupon booklet  with the local newspaper for delivery

Explanation:

George focus on promotion rather than using the other stores strategy of word-of-mouth. Different types of promotion: advertising, public relations, direct selling and sales promotions.A temporary reduction in the price, such as 50% off. Reduction amount  may be a percentage that can be marked on the package.A coupon booklet is inserted into the local newspaper for delivery. Also on checkout  the customer can be given a coupon based on products purchased. The consumer is automatically entered into the contest/event by purchasing the product.

Displays:-

A board on which messages are written in crayon.

Consumers get one sample for free, after their trial and then could decide whether to buy or not

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A scientist compares two samples of colorless gas present at the beginning and end of a lab process. She wants to determine whet
kompoz [17]

Joseph Priestley was born in Yorkshire, the eldest son of a maker of wool cloth. His mother died after bearing six children in six years. Young Joseph was sent to live with his aunt, Sarah Priestley Keighley, until the age of 19. She often entertained Presbyterian clergy at her home, and Joseph gradually came to prefer their doctrines to the grimmer Calvinism of his father. Before long, he was encouraged to study for the ministry. And study, as it turned out, was something Joseph Priestley did very well.

Aside from what he learned in the local schools, he taught himself Latin, Greek, French, Italian, German and a smattering of Middle Eastern languages, along with mathematics and philosophy. This preparation would have been ideal for study at Oxford or Cambridge, but as a Dissenter (someone who was not a member of the Church of England) Priestley was barred from England's great universities. So he enrolled at Daventry Academy, a celebrated school for Dissenters, and was exempted from a year of classes because of his achievements.

After graduation, he supported himself, as he would for the rest of his life, by teaching, tutoring and preaching. His first full-time teaching position was at the Dissenting Academy in Warrington. (Although obviously brilliant, original, outspoken and, by one report, of "a gay and airy disposition," Priestley had an unpleasant voice and a sort of stammer. That he made a living through lectures and sermons is further evidence of his extraordinary nature.)


 https://www.acs.org/content/acs/en/education/whatischemistry/landmarks/josephpriestleyoxygen.html

8 0
3 years ago
Read 2 more answers
When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion. Which o
Setler [38]

<u>Answer:</u>

Option: D. Gravity is pulling the crash test dummy in the direction the car is moving.

<u>Explanation: </u>

When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion because the gravity is pulling the crash test dummy in the direction the car is moving.  

Basically when the car is starting, the person inside is in static position and the car is going to move. So it is putting a force on the person to move on the same speed. But as the person is sitting static hence gravity is pulling him behind from moving. Hence, The dummy appears to be pressed backward.

7 0
3 years ago
The Indianapolis Motor Speedway has four banked curves, each of which forms a quarter of a circle. Suppose a race car speeds alo
boyakko [2]

Answer:

r =  255.68 m

Explanation:

When a body moves in a circular path, an acceleration, due to constant change in its direction, is developed, known as centripetal acceleration. The centripetal acceleration acts towards the center of the circular path. The formula to calculate the centripetal acceleration is given as follows:

ac = v²/r

where,

ac = centripetal acceleration = 22 m/s²

v = tangential speed = 75 m/s

r = radius of curve = ?

Therefore,

22 m/s² = (75 m/s)²/r

r = (75 m/s)²/(22 m/s²)

<u>r =  255.68 m</u>

4 0
3 years ago
what is the distance moved by a particle moving along x axis if it starts from x=-7m goes upto x= -12m turns and stops at x=+34m
Marizza181 [45]

Answer: Trajectory=51m

Displacement=41m

Explanation:

Let's begin by stating clear that <u>movement is the change of position of a body at a certain time.</u> So, during this movement, the body will have a trajectory and a displacement, being both different:

The trajectory is the path followed by the body (is a scalar magnitude).  

The displacement is the distance in a straight line between the initial and final position (is a vector magnitude).  

According to this, in the description of the object placed at x= -7m on a number line and moving some 12m to the left and then to the right, stopping at x=34m; we are talking about the path followed by the object, hence its <u>trajectory</u>. So, 51 m is its trajectory.

But, if we talk about displacement, we have to draw a straight line between the initial position of the object (x=-7m) to its final position (x=+34m).

Now, being this an unidimensional problem, the displacement vector for this object is 41m.

7 0
3 years ago
What is the speed of light (in m/s) in air? (Enter your answer to at least four significant figures. Assume the speed of light i
jenyasd209 [6]

Answer:

The speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

Explanation:

To find the speed of light in air and in polystyrene we need to use the following equation:

c_{m} = \frac{c}{n}

Where:

c_{m}: is the speed of light in the medium

n: is the refractive index of the medium

In air:

c_{a} = \frac{c}{n_{a}} = \frac{2.997 \cdot 10^{8} m/s}{1.0003} = 2.996 \cdot 10^{8} m/s

In polystyrene:

c_{p} = \frac{c}{n_{p}} = \frac{2.997 \cdot 10^{8} m/s}{1.6} = 1.873 \cdot 10^{8} m/s  

Therefore, the speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

I hope it helps you!

8 0
3 years ago
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