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xenn [34]
3 years ago
6

George created an advertisement for a retail store that sold clothes. He added a discount in the form of a coupon that the custo

mers had to redeem at the store within the next week. Which advertising feature did George use in his advertisement?
Physics
1 answer:
likoan [24]3 years ago
7 0

Answer:

The advertisement feature that George can use is a coupon booklet  with the local newspaper for delivery

Explanation:

George focus on promotion rather than using the other stores strategy of word-of-mouth. Different types of promotion: advertising, public relations, direct selling and sales promotions.A temporary reduction in the price, such as 50% off. Reduction amount  may be a percentage that can be marked on the package.A coupon booklet is inserted into the local newspaper for delivery. Also on checkout  the customer can be given a coupon based on products purchased. The consumer is automatically entered into the contest/event by purchasing the product.

Displays:-

A board on which messages are written in crayon.

Consumers get one sample for free, after their trial and then could decide whether to buy or not

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Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 22oC and exits at 2.0
KonstantinChe [14]

Answer:

The  the quality of the refrigerant at the exit of the expansion valve is 0.179.

Explanation:

Given that,

Initial pressure = 10 bar

Temperature = 22°C

Final pressure = 2.0 bar

We using the value of h

h = 293.4\ kJ/kg

The refrigerant during expansion undergoes a throttling process

Therefore, h_{1}=h_{2}

We need to calculate the quality of the refrigerant at the exit of the expansion valve

At 2.0 bar,

The property of ammonia

h_{f}=47.8 kJ/kg

h_{g}=1417.7 kJ/kg

Using formula

h_{2}=h_{f}+x(h_{g}-h_{f})

Put the value into the formula

293.4 =47.8+x(1417.7-47.8)

x=\dfrac{293.4-47.8}{1417.7-47.8}

x=0.179

Hence, The  the quality of the refrigerant at the exit of the expansion valve is 0.179.

6 0
3 years ago
A. Blue light has higher energy than red light. Write 3 - 4 sentences comparing these electromagnetic waves with respect to the
frosja888 [35]

PART A)

As we know that energy of light depends on its wavelength and frequency as following formula

E = \frac{hc}{\lambda} = h\nu

now we know that wavelength of blue light is less than the red light so here energy of blue light will be more

also we know that

\nu = \frac{c}{\lambda}

so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium

PART B)

Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy

When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.

here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current

So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current

5 0
3 years ago
Read 2 more answers
A proton moves with a speed of 1.17 105 m/s through Earth's magnetic field, which has a value of 50.0 µT at a particular locatio
vlabodo [156]

a) Southward you need to apply right hand rule. If you close your hand to the east, your thumb will indicate south.

b) Given the equation for Magnetic Force

F= qVB

Replacing

F= (1.16*10^{-19})(1.17*10^5)(50*10^{-6})

F=9.36*10^{-19}

c) Given the second Newton's Law by

F_g = 1.67*10^{-27}*9.81

F_g = 1.64*10^{-26}

Given the electric force by,

F_e = 1.6*10^{-19}*1.5*10^2

F_e = 2.4*10^{-17}N

F=9.36*10^{-19}N

7 0
2 years ago
A model rocket is launched directly upward at a speed of 16 meters per second from a height of 2 meters. The function f(t)=−4.9t
Crank

Answer:

Hmax=15.06 meters

Explanation:The question ask for the maximum value of the function f(t) which can be find by find the maxima of the function

The maxima of the function occurs when the slope is zero. i.e.

\frac{df}{dt} =0\\\frac{df}{dt} =\frac{d}{dt} (-4.9t^2+16t+2)\\\frac{df}{dt} =-4.9*2t+16\\-9.8t+16=0\\t=16/9.8\\t=1.63 secs

Hence the maxima occurs at t=1.63 seconds

The maximum value of f is

f(1.63)=-4.9(1.63^2)+16(1.63)+2\\f(1.63)=15.06\\

hence maximum height is found to be

Hmax=15.06 meters

8 0
3 years ago
Does a car that is slowing down always have a negative acceleration explain
Zina [86]
No, because sometimes you have to stop at stop signs and stop lights.
4 0
3 years ago
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