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xenn [34]
3 years ago
6

George created an advertisement for a retail store that sold clothes. He added a discount in the form of a coupon that the custo

mers had to redeem at the store within the next week. Which advertising feature did George use in his advertisement?
Physics
1 answer:
likoan [24]3 years ago
7 0

Answer:

The advertisement feature that George can use is a coupon booklet  with the local newspaper for delivery

Explanation:

George focus on promotion rather than using the other stores strategy of word-of-mouth. Different types of promotion: advertising, public relations, direct selling and sales promotions.A temporary reduction in the price, such as 50% off. Reduction amount  may be a percentage that can be marked on the package.A coupon booklet is inserted into the local newspaper for delivery. Also on checkout  the customer can be given a coupon based on products purchased. The consumer is automatically entered into the contest/event by purchasing the product.

Displays:-

A board on which messages are written in crayon.

Consumers get one sample for free, after their trial and then could decide whether to buy or not

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Consider the following list of numbers. 129, 685, 125, 511, 601, 52, 46 The height of a binary search tree is the maximum number
NemiM [27]

Answer:

The height of the tree is three (3) deep

Explanation:

It's 3 deep

Under 129, comes 125 and 685;

Under 125, comes 52 : Under 685, comes 511;

Under 52, comes 46 : Under 511, is 601.

This is illustrated below.

129

∧

125,685

|,|

52,511

|,|

46,601

5 0
3 years ago
A charge q produces an electric field of strength 2E at a distance of d away. Determine the electric field strength at a distanc
Alja [10]

The electric field strength of a point charge is inversely proportional to the square of the distance from the charge ... a lot like gravity.

If the magnitude of the field is (2E) at the distance 'd', then at the distance '2d', it'll be (2E)/(2²).  That's (2E)/4 = 0.5E .

3 0
3 years ago
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A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, wha
tigry1 [53]

work done = force * distance moved (in direction of the force)

force= mass* acceleration 

force=58.1N

58.1*(5.8*10^4)
=3,369,800 J
3 0
3 years ago
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The magnetic force on a straight wire 0.69 m long is 1.5 x 10-3 N. The current in the wire is 16.9 A. What is the magnitude of t
VikaD [51]

Answer:

Magnitude of magnetic field is 1.29 x 10⁻⁴ T

Explanation:

Given :

Current flowing through the wire, I = 16.9 A

Length of wire. L = 0.69 m

Magnetic force experienced by the wire, F = 1.5 x 10⁻³ N

Consider B be the applied magnetic field.

The relation to determine the magnetic force experienced by current carrying wire is:

F = ILBsinθ

Here θ is the angle between magnetic field and current carrying wire.

According to the problem, the magnetic field and current carrying wire are perpendicular to each other, that means θ = 90⁰. So, the above equation becomes:

F = ILB

B=\frac{F}{IL}

Substitute the suitable values in the above equation.

B=\frac{1.5\times10^{-3} }{16.9\times0.69}

B = 1.29 x 10⁻⁴ T

7 0
4 years ago
Question 5 of 10
ElenaW [278]

Answer:

B it is b because thermal will move from boiling water to the ice

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3 years ago
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