Answer:
v=12.5 i + 12.5 j m/s
Explanation:
Given that
m₁=m₂ = m
m₃ = 2 m
Given that speed of the two pieces
u₁=- 25 j m/s
u₂ =- 25 i m/s
Lets take the speed of the third mass = v m/s
From linear momentum conservation
Pi= Pf
0 = m₁u₁+m₂u₂ + m₃ v
0 = -25 j m - 25 i m + 2 m v
2 v=25 j + 25 i m/s
v=12.5 i + 12.5 j m/s
Therefore the speed of the third mass will be v=12.5 i + 12.5 j m/s
Answer:
The deceleration is
Explanation:
From the question we are told that
The distance of the car from the crossing is
The speed is
The reaction time of the engineer is
Generally the distance covered during the reaction time is
=>
=>
Generally distance of the car from the crossing after the engineer reacts is
=>
=>
Generally from kinematic equation
Here v is the final velocity of the car which is 0 m/s
So
=>