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3 years ago

The chemical reaction Na+ + Cl- NaCl is best described as a(n) _____.

Chemistry

2 answers:

muminat3 years ago

7 0

Ionic bond because transfer of electrons is taking place

Snowcat [4.5K]3 years ago

5 0

A combination reaction. This is because two elements combined to form one compound.
Hope this helped.

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Calculate the [oh−] in a solution with a ph of 12.52.

BaLLatris [955]

PH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M

6 0

3 years ago

How many moles in 2.21 x10E24 atoms of aluminum

lisov135 [29]

<h3>Answer:</h3>

3.67 mol Al

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.21 × 10²⁴ atoms Al

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 2.21 \cdot 10^{24} \ atoms \ Al(\frac{1 \ mol \ Al}{6.022 \cdot 10^{23} \ atoms \ Al})$
Divide: $\displaystyle 3.66988 \ mol \ Al$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.66988 mol Al ≈ 3.67 mol Al

7 0

3 years ago

1) Given the balance equation below. Calculate how much Na3PO4 in grams you

juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

$Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}$

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

$\frac{164}{120}$

100 grams of NaOH is produced from =

$\frac{164}{120}\times100$ gram of Na3PO4

calculate,

= 136.67 g

8 0

3 years ago

If 1.9 kJ of heat is transferred to 96 g aluminum at 113°C, what would the

erastova [34]

Answer:

T2 = 135.1°C

Explanation:

Given data:

Mass of water = 96 g

Initial temperature = 113°C

Final temperature = ?

Amount of energy transfer = 1.9 Kj (1.9×1000 = 1900 j)

Specific heat capacity of aluminium = 0.897 j/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Now we will put the values in formula.

Q = m.c. ΔT

1900 j = 96 g × 0.897 j/g.°C × T2 - 113°C

1900 j = 86.112 j/°C × T2 - 113°C

1900 j / 86.112 j/°C = T2 - 113°C

22.1°C + 113°C = T2

T2 = 135.1°C

4 0

3 years ago

When potassium metal is added to water, a violent reaction occurs that releases a tremendous amount of light and thermal energy.

Thepotemich [5.8K]

Answer:

An Exothermic reaction.

Explanation:

An exothermic reaction produces heat, while endothermic reactions absorb heat

5 0

3 years ago