Question

A gas engine is 6% efficient. What portion of a 12 gallon tank of gas is wasted?

Answer 1

Answer:

282/25

Step-by-step explanation:

$efficient \: = 12 \times \frac{6}{100} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{72}{100} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{18}{25 } \\ so \: \\ west \: = 12- \frac{18}{25} \\ \: \: \: \: \: \: \: \: \: \: \: \: = \frac{282}{25} \: \: gallon$

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Answer 2

Answer:19.74 gallons of the gas in the tank is wasted.

Step-by-step explanation:

Since the efficiency of the gas engine is 6%, wastage is #= 100 - 6 = 94%.

Therefore wastage = 94% x 21=94 x21/100=19.74 gallons