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Serjik [45]
3 years ago
5

If a toy car with a coin on top of it is rolling down a hill what force is keeping the coin on top of the car?

Physics
1 answer:
forsale [732]3 years ago
7 0
The answer is gravity.
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You buy a 75 watt light bulb. the label means that
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The label means that the bulb will consume 75 joules of electrical energy in 1 sec
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Thomson's experiments accounted for: the mass of the electron the fundamental charge the force on a current-carrying wire the el
gogolik [260]

Thomson experiment he calculated the charge to mass ratio just be passing the fundamental charge through a tube

He calculated the charge to mass ratio just by finding the deflection of charge while it is passing through the constant electric field

so here we will use the deflection as following

let say it passes the field of length "L"

so here we have

t = \frac{L}{v}

now in the same time if it deflect by some distance

\delta y = \frac{1}{2}at^2

\delta y = \frac{1}{2}{eE}{m}t^2

now by solving this equation we can find e/m ratio

so here correct answer will be

the electron's charge-to-mass ratio

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3 years ago
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What unit do we use for pressure
-Dominant- [34]

Answer:

Pascal

Explanation:

5 0
3 years ago
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A child on a sled is perched at the top of a hill, at a height 7.0 m above the base of the hill. The total mass of the girl plus
spin [16.1K]

Answer:

a)11,71 m/s

b)12.73 m/s

Explanation:

We apply the conservation principle because there is no friction between the hill and the sled:

Total initial energy (Ei) = Total initial energy (Ef), Equation(1)

We define:

K = Kinetic energy = \frac{1}{2}*m*v^{2}

U = Potential energy = m*g*h

m = mass (kg)

v = velocity (m/s)

h = height (m)

g = gravity acceleration = 9.8m/s^{2}

A)  hi=7m, hf=0 ,vi=0 , vf=?

   Ei=Ef\\Ki+Ui=Kf+Uf

1/2*m*vi^{2} +m*g*hi= 1/2*m*vf^{2} +m*g*hf

0+m*g*hi=1/2*m*vf^{2}+0

(2*m*g*hi)/m=vf^{2}

vf=\sqrt{2*g*hi}

vf=\sqrt{2*9.8*7}

vf=11.71 m/s

Answer: She reaches the base of the hill with speed of 11.22 m/s

B) hi=7 m, vi=5 m/s, hf=0, vf=?

m*g*hi+1/2*m*vi^{2} =m*g*hf+1/2*m*vf^{2}

We divide all terms by m

g*hi+1/2vi^{2} =g*hf+1/2*vf^{2}

9.8*7+1/2*5^{2} =1/2*vf^{2}

2(68.6+12.5)=vf^{2}

162.2=vf^{2}

vf=\sqrt{162.2}

vf=12.73 m/s

Answer: She will move with a speed of 12.73 m/s when she reaches the base of the hill

3 0
3 years ago
The electric potential in a region of uniform electric field is -1600 V at x = -1.30 m and + 2000 V at x =+ 1.80 m . What is Ex?
Inga [223]

Answer:

-1161.29 V/m

Explanation:

The x component of electric field will be given by

E_x= -\frac {\triangle V}{\triangle x}

Here \triangle V is the change in voltage while triangle x is the change in x

E_x= -\frac {+2000 V--1600V}{\triangle 1.8--1.3}=-\frac {3600}{3.1}=-1161.29 V/m

6 0
3 years ago
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