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irga5000 [103]
3 years ago
10

5. which event marks the end of both the Paleozoic era and the mesozoic era?

Physics
2 answers:
olganol [36]3 years ago
6 0
The answer is A. Cenozoic
Kruka [31]3 years ago
5 0
I'm not sure but The end of the mesozoic era is marked by A.Cenozoic
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Two liquids, A and B, have equal masses and equal initial temperatures. Each is heated for the same length of time over identica
DochEvi [55]

Answer:

So the specific heat of the liquid B is greater than that of A.

Explanation:

Liquid A is hotter than the liquid B after both the liquids are heated identically for the same duration of time from the same initial temperature then according to heat equation,

Q=m.c.\Delta T

where:

m = mass of the body

c = specific heat of the body

\Delta T= change in temperature of the body

The identical heat source supplies the heat for the same amount of time then the quantity of heat supplied is also equal.

So for constant heat, constant mass the temperature change is inversely proportional to the specific of heat of the liquid.

\Delta T=\frac{Q}{m} \times \frac{1}{c}

\Delta T\propto\frac{1}{c}

So the specific heat of the liquid B is greater than that of A.

5 0
3 years ago
If a 100 N net force acts on a 50 kg car, what will the acceleration of the car will be?
Allushta [10]
According to newton's law Force = mass * acceleration
so , 100 = 50 * a
so , a= 2 m/s^2
6 0
4 years ago
Describe the water cycle process starting from an afternoon thunderstorm. There are many different variations that could happen.
spin [16.1K]

Explanation:

The water cycle basically involves five steps:

  • evaporation and transpiration ⇄
  • condensation, ⇄
  • precipitation, ⇄
  • runoff, ⇄
  • infiltration ⇄

So when a <u>thunderstorm </u>occurs it <em>helps in completing the precipitation process </em>by enabling the release of water vapor stored up in the atmosphere to fall on the ground as rain.

After this, the water <em>runoffs </em><em>to the surface of the ground, on plants, into rocks, rivers, and lakes.</em>

Next, the <em>Infiltration process</em> enables the water on the ground surface to enter the soil some of which becomes groundwater.

The cycle begins again as the<em> </em><em>evaporation and transpiration</em> <em>process </em>begins, where the groundwater as a result of heat from the sun is taken back into the atmosphere, while water in plants by means of transpiration goes back <em>into the atmosphere</em>.

It then <em>condenses </em>and falls back as precipitation again.

3 0
3 years ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.0 m/s. Th
elena55 [62]

<u>Answer:</u>

<em>Thunderbird is 995.157 meters behind the Mercedes</em>

<u>Explanation:</u>

It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird  decided to take a pit stop and slows down for 250 m. She spent 5 seconds  in the pit stop.

Here final velocity v=0 \ m/s

initial velocity u= 71 m/s  distance  

Distance covered in the slowing down phase = 250 m

v^2-u^2=2as

a= \frac {(v^2-u^2)}{2s}

a = \frac {(0^2-71^2)}{(2 \times 250)}=-10.082 \ m/s^2

v=u+at

t= \frac {(v-u)}{a}

= \frac {(0-71)}{(-10.082)}=7.042 s

t_1=7.042 s

The car is in the pit stop for 5s t_2=5 s

After restart it accelerates for 350 m to reach the earlier velocity 71 m/s

a= \frac {(v^2-u^2)}{(2\times s)} = \frac{(71^2-0^2)}{(2 \times 370)} =6.81 \ m/s^2

v=u+at

t= \frac{(v-u)}{a}

t= \frac{(71-0)}{6.81}= 10.425 s

t_3=10.425 s

total time= t_1 +t_2+t_3=7.042+5+10.425=22.467 s

Distance covered by the Mercedes Benz during this time is given by s=vt=71 \times 22.467= 1595.157 m

Distance covered by the Thunderbird during this time=250+350=600 m

Difference between distance covered by the Mercedes  and Thunderbird

= 1595.157-600=995.157 m

Thus the Mercedes is 995.157 m ahead of the Thunderbird.

6 0
3 years ago
PLEASE ANSWER ASAP!!!
Mice21 [21]

The total momentum of the system has to be conserved to satisfy the principle of conservation of momentum. Before the ball hits the bottle, the momentum of the system is 0.4 x 18 = 7.2 kg m/s

The momentum of the bottle after being hit is 0.2 x 25 = 5 kg m/s

So the momentum of the ball now is 7.2 - 5 = 2.2 kg m/s

Hence its velocity is 2.2/0.4 = 5.5 m/s

3 0
3 years ago
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