Answer:
(b) Vl/v
Explanation:
The dimension for V is LT-1
The dimension for Length is L
The dimension for time is T
The fluid property v has a dimension of L2T-1, which is equal to square of the length divided by time.
for (a) Vlv
LT-1×L× L2T-1
= L^4T^-2
(b) Vl/v
LT^-1 ×L/ L^2 T^-1
=1. ; this is dimensionless.
(c)V2v
(LT^-1)^2 × L^2 T^-1
= L^4 T^-3
(d) V/(lv)
LT^-1/(LL^2 T^-1)
= L^-2
B)
Two bodies with the same vibration frequency that are placed next to each other will exhibit sympathetic vibrations as one body causes the other to vibrate.
Answer:
viscosity = 0.051725 N/m-s
Explanation:
Given data
diameter = 0.3 m
u(r) = 0.4/r - 1000r m/s
diameter d1 = 2 cm = 0.02 m
diameter d2 = 4 cm = 0.04 m
rotation = 500 rpm
power = 1 w
to find out
fluid viscosity
solution
we have given
u(r) = 0.4/r - 1000r m/s
du/dr = -0.4/r² + 1000
here r = 0.3 /2 = 0.01 m
du /dr = -0.4/(0.01)² + 1000
du/dr = 5000
and
so velocity is
force = viscosity ( 2π×r×L) du/dr
0.026 / 0.02 = viscosity ( 2π× 0.02×0.04) 5000
viscosity = 0.051725 N/m-s
Answer:22 m/s
Explanation:
Given
launch angle
height of goal
and horizontal distance
Suppose initial speed is
Trajectory of a Projectile is given by
substituting the values we get
So, initial launch speed is