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Rom4ik [11]
3 years ago
8

Another metal phosphate is iron phosphate. It will behave similar to calcium phosphate in an acid solution. What is the net ioni

c equation including phases for FePO4(s) dissolving in H3O+(aq)?
Chemistry
2 answers:
Ivenika [448]3 years ago
5 0

The net ionic equation is \boxed{{\text{FeP}}{{\text{O}}_4}\left(s\right)+{{\text{H}}_3}{{\text{O}}^+}\left({aq}\right)\to{\text{F}}{{\text{e}}^{3+}}\left({aq}\right)+{\text{HPO}}_4^{2-}\left({aq}\right)+{{\text{H}}_2}{\text{O}}\left(l\right)}

Further Explanation:

The three types of equations that are used to represent the chemical reaction are as follows:

1. Molecular equation

2. Total ionic equation

3. Net ionic equation

The reactants and products remain in <em>undissociated</em> form in <em>molecular equation</em>. In the case of <em>total ionic equation</em>, all the ions that are <em>dissociated</em> and present in the reaction mixture are represented while in the case of net or overall ionic equation only the useful ions that participate in the reaction are represented.

The steps to write the net ionic reaction are as follows:

Step 1: Write the molecular equation for the reaction with the phases in the bracket.

In the reaction, {\text{FeP}}{{\text{O}}_4} ionizes in aqueous medium to form {\text{F}}{{\text{e}}^{3+}} and {{\text{H}}_{\text{2}}}{\text{O}}. The balanced molecular equation of the reaction is as follows:

{\text{FeP}}{{\text{O}}_4}\left(s\right)+{{\text{H}}_3}{{\text{O}}^+}\left({aq}\right)\to{\text{F}}{{\text{e}}_2}{\left({{\text{HP}}{{\text{O}}_4}}\right)_3}\left({aq}\right)+{{\text{H}}_2}{\text{O}}\left(l\right)

Step 2: Dissociate all the compounds with the aqueous phase to write the total ionic equation. The compounds with solid and liquid phase remain same. The total ionic equation is as follows:

{\text{FeP}}{{\text{O}}_4}\left(s\right)+{{\text{H}}_3}{{\text{O}}^+}\left({aq}\right)\to{\text{F}}{{\text{e}}^{3+}}\left({aq}\right)+{\text{HPO}}_4^{2-}\left({aq}\right)+{{\text{H}}_2}{\text{O}}\left(l\right)

Step 3: The common ions on both the sides of the reaction get cancelled out to get the net ionic equation.

{\text{FeP}}{{\text{O}}_4}\left(s\right)+{{\text{H}}_3}{{\text{O}}^+}\left({aq}\right)\to{\text{F}}{{\text{e}}^{3+}}\left({aq}\right)+{\text{HPO}}_4^{2-}\left({aq}\right)+{{\text{H}}_2}{\text{O}}\left(l\right)

Therefore, the net ionic equation obtained is as follows:

{\text{FeP}}{{\text{O}}_4}\left(s\right)+{{\text{H}}_3}{{\text{O}}^+}\left({aq}\right)\to{\text{F}}{{\text{e}}^{3+}}\left({aq}\right)+{\text{HPO}}_4^{2-}\left({aq}\right)+{{\text{H}}_2}{\text{O}}\left(l\right)

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: net ionic equation, FePO4, H3O+, Fe3+, HPO42-, H2O, aqueous phase, dissociate, molecular equation, water.

crimeas [40]3 years ago
4 0
<span>Iron phosphate when in an acid solution ionizes or dissociates into ions. The ions are the Iron (III) and the HPO4^2-. The net ionic equation should be as follows:

FePO4(s)+H3O +(aq)⇌Fe^3+(aq)+HPO4^2−(aq)+H2O(l)</span>
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False

Explanation:

Electron affinity is negative when energy is absorbed and it is positive when energy is released.

Electron affinity is defined as the energy released in adding an electron to a neutral atom in the gas phase.

It is a measure of the readiness of an atom to gain an electron.

In a reaction where energy is released, electron affinity is usually positive. These reactions are called exothermic reactions.

Endothermic reactions in which energy is absorbed have negative electron affinity values.

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3 years ago
According to the law of definite proportions, if a sample of a compound contains 24.00 grams of carbon and 4.00 grams of hydroge
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Explanation:

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6 0
2 years ago
2Na(s) + 2H,O(l) — 2NaOH(?) + H, (g)<br> 0 what is the missing symbol
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3 0
2 years ago
Control of Blood pH by respiratory rate.
nata0808 [166]

Answer:

A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system

B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in  H^+ which is directly proportional to the increase in Blood PH levels

C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid

Explanation:

A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system

CO_{2} +H_{2} O ⇄ H^+ + HCO^-_{3}

B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in  H^+ which is directly proportional to the increase in Blood PH levels

C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid

6 0
3 years ago
g A microwave oven heats by radiating food with microwave radiation, which is absorbed by the food and converted to heat. If the
Sliva [168]

Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass =  Volume ×  Density

Thus; the mass of the water =  250 mL ×  1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature T_1 = 20.0° C

the final temperature T_2 = 99° C

Change in temperature \Delta T = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms \Delta T

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = 6.626 \times 10^{-34} \ J.s

c = velocity of light = 3.0 \times 10^8 \ m/s

=  \dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{0.125}

= 1.59024 \times 10^{-24} J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = \dfrac{82555 J}{1.59024 \times 10^{-24}J}

The total photons required = 5.19 × 10²⁸ photons

5 0
3 years ago
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