Energy Conservation:
1 answer:
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Answer: 0.56 m/s
Explanation:
hello, there is 25° inclination angle for the chute in the drawing. Thankfully, I know this problem. The conservation of momentum.
so there are X and Y components for the momentum in this problem. The Y component is not conserved as when the coal gets in the cart, the normal force exerted by the surface reduces it to 0.
Now, the X component is definitely conserved here.
so you have the momentum of the cart which is 440*0.5 added to the momentum of the chunk which is 150*0.8*cos(25°), that is the momentum before the coupling between the objects. Afterwards both objects will have the same velocity, so we write the equation like this:
Answer:
x = 1.018 m
Explanation:
given,
height of man = 190 cm
= 1.9 m
scale reading on left = 450 N
scale reading on the right = 390 N
Let center of gravity of man be x distance from feet, feet is on right side.
For system to be in equilibrium moment about center should be equal to zero.
∑M = 0
now,
450(1.9 - x ) - 390 × x = 0
450(1.9 - x ) = 390 × x
855 - 450 x = 390 x
840 x = 855
x = 1.018 m
hence, point of center of gravity from feet is equal to x = 1.018 m