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Radda [10]
3 years ago
7

At which temperature would an object radiate the least amount of electromagnetic energy?

Chemistry
1 answer:
dexar [7]3 years ago
8 0
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A student performs an experiment to determine the molar mass of magnesium oxide. The student repeats the experiment five times a
mestny [16]

Answer:

Percent relative error = 0.191%

Explanation:

Relative error is a measure of accuracy (How closeness is the measure to the accepted value) for a determined data. The formula is:

Percent relative error = |Experimental - Accepted| / Accepted * 100

<em>Where experimental is the average of the data:</em>

(40.220g/mol + 40.654g/mol + 40.314g/mol + 40.165g/mol + 40.554g/mol) / 5 =

40.381g/mol

Replacing using accepted value = 40.304g/mol:

|40.381g/mol - 40.304g/mol| / 40.304g/mol * 100

<h3>Percent relative error = 0.191%</h3>
5 0
3 years ago
oth hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you opene
Ksju [112]

Answer: Odor of ammonia would we detect first on the other side of the room.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{M_{NH_3}}{M_{H_2S}}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{17.031}{34.1}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=0.71

Thus the odor of ammonia would we detect first on the other side of the room as the rate of effusion of ammonia would be faster as it has low molecular weight as compared to hydrogen sulphide.

5 0
3 years ago
Read 2 more answers
To three significant digit,what is the mass percentage of iron in the compound Fe2O3​
svlad2 [7]

69.9%

Explanation:

To find the mass percentage of iron in the compound in Fe₂O₃, we would go ahead to express the given molar mass of the iron to that of the compound.

 Mass percentage  = \frac{molar mass of Fe}{Molar mass of Fe_{2}O_{3}  }  x 100

Molar mass of Fe = 55.85g/mol

Molar mass of O = 16g/mol

Molar mass of Fe₂O₃ = 2(55.85) + 3(16) = 159.7‬g/mol

Mass percentage  = \frac{2(55.85)}{159.7}  x  100   = 69.94% = 69.9%

learn more:

Mass percentage brainly.com/question/8170905

#learnwithBrainly

4 0
3 years ago
Question 10
olga2289 [7]

Answer:

Here it would be A,B and C because all the examples are violating safety precautions. They are all examples of un safe signs.

Hope this helps

Explanation:

6 0
2 years ago
Which of the following units are commonly used in chemistry? A Kelvin b ampere c fluid ounce d kilogram ​
sdas [7]

Explanation:

your answer is Kelvin because it is the SI unit of temperature

7 0
2 years ago
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