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anzhelika [568]
3 years ago
8

If you get some of the right sort of organic material, and heat it in the right sort of way, perhaps with a little squeezing, yo

u will end up with coal. The most-heated is the most valuable. In order, from the MOST-VALUABLE/MOST-HEATED (FIRST) to the least-valuable/least-heated (LAST), the coals (and material that gives coal) are:
Chemistry
1 answer:
AnnZ [28]3 years ago
3 0

Question Options:

A) Bituminous, peat, lignite, anthracite.

B) Anthracite, bituminous, lignite, peat.

C) Peat, anthracite, lignite, bituminous.

D) Peat, lignite, bituminous, anthracite.

E) Bituminous, peat, anthracite, lignite.

Answer: Anthracite, bituminous, lignite, peat.

Explanation:

Anthracite is a form of carbonized ancient plants; the hardest and cleanest-burning of all the coals.

Bituminous is a form of coal that is characterized by mineral pitch; a black, tarry substance, burning with a bright flame.

Lignite is a low grade brownish coal.

Peat is a form of coal formed of dead but not fully decayed plants found in bog areas, often burned as fuel.

From the definitions given above, one can categorically say the most heated is in a descending order. And According to the Question, most heated is most valuable.

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Assuming that the experiments performed in the absence of inhibitors were conducted by adding 5 μl of a 2 mg/ml enzyme stock sol
prohojiy [21]

Hey there!:

From the given data ;

Reaction  volume = 1 mL , enzyme content = 10 ug ( 5 ug in 2 mg/mL )

Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:

[E]t in molar  = g/L * mol/g

[E]t  = 0.01 g/L * 1 / 45,000

[E]t = 2.22*10⁻⁷

Vmax = 0.758 umole/min/ per mL

= 758 mmole/L/min

=758000 mole/L/min => 758000 M

Therefore :

Kcat = Vmax/ [E]t

Kcat = 758000 / 2.2*10⁻⁷ M

Kcat = 3.41441 *10¹² / min

Kcat = 3.41441*10¹² / 60 per sec

Kcat = 5.7*10¹⁰ s⁻¹

Hence   kcat of   xyzase is  5.7*10¹⁰ s⁻¹


Hope that helps!



4 0
3 years ago
Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)<->Zn2+(aq
Simora [160]

Hey there!


We Know that:



 2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)


The equilibrium expression for the reaction is:



Kc =  [ Zn⁺² ]  /  [Ag⁺ ]²


Hope that helps!

8 0
3 years ago
Read 2 more answers
How many particles are in 7.07x10^-6 moles of a substance?
Butoxors [25]

Answer:

4.25*10^18

Explanation:

1 mole =6.023*10^23 particles

so 7.07*10^-6 mole=6.023*10^23*7.07*10^-6 particles=4.25*10^18 particles

5 0
3 years ago
Outline two methods used by designers to assemble packages​
Lostsunrise [7]

Answer:

Product packaging design refers to the production of a product's exterior. Develop an organization. All these specifics allow one to consider what the sealed substance is about how to use it, who can use it, and maybe, What do you sell? For your product, there are several different packaging forms available.

Explanation:

8 0
2 years ago
A student titrates a 20.00 mL sample of an aqueous borax solution with 1.03 M H2SO4. If 2.07 mL of acid are needed to reach the
RSB [31]

Answer:

The concentration of the borax solution is 0.1066 M

Explanation:

Step 1: Dtaa given

Volume of a sample of aqueous borax solution = 20.00 mL = 0.020 L

Molarity of H2SO4  = 1.03 M

Volume of the H2SO4 = 2.07 mL = 0.00207 L

Step 2: The balanced equation

Na2B4O7*10H2O(borax) + H2SO4 ⇆ Na2SO4 + 4 H3BO3 + 5 H2O

Step 3: Calculate molarity of borax solution

b*Ca*Va = a * Cb*Vb

⇒with B = the coefficient of H2SO4 = 1

⇒with Ca = the concentration of borax = TO BE DETERMINED

⇒with Va = the volume of borax = 0.020 L

⇒with a = the coefficient of borax = 1

⇒with Cb = the concentration of H2SO4 = 1.03 M

⇒with Vb = the volume of H2SO4 = 0.00207 L

Ca*0.020 L = 1.03 M * 0.00207 L

Ca = (1.03 * 0.00207) / 0.020

Ca = 0.1066 M

The concentration of the borax solution is 0.1066 M

6 0
3 years ago
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