Answer:
In an experiment, a student transferred 4.50 mL of a liquid into a pre-weighed beaker (the weight of which was determined to be 35.986 g ).
Explanation:
<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>HELPS</em><em> </em><em>YOU</em><em> </em>
<em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em>
Answer:
The another word for microorganism is microbe
To be honest, I can’t really see the question. So please next time just type it out lol
This would be C. A car rusting
94.6 g. You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.
We can use a version of the <em>dilution formula</em>
<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2
where
<em>m</em> represents the mass and
<em>C</em> represents the percent concentrations
We can rearrange the formula to get
<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)
<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %
<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %
∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g
