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xxMikexx [17]
3 years ago
7

a. Choose the best response for the following. The ionization energy for the chlorine atom is equal in magnitude to the electron

affinity for A) Cl- ion B) Cl+ ion C) F atom D) Cl atom E) none of these b. Choose the best explanation for this. A) The electron affinity can’t be determined without detecting the ionization energy. B) These energies are equal for all forms of the same element. C) Electron affinity doesn’t exist for these substances. D) Two particles participate in the same process, both energies being involved. Submit AnswerTry
Chemistry
1 answer:
Lunna [17]3 years ago
3 0

A) Cl- ion

B) These energies are equal for all forms of the same element

Explanation:

The ionization energy for a chlorine atom is equal in magnitude to the electron affinity of Cl⁻ ion because these energies are equal for all forms of the same element.

  • Electron affinity is the energy released  in adding an electron to  a neutral atom in the gas phase.
  • Ionization energy is the amount of energy required for the removal of an electron in atom or ion.
  • Here the energy released when an electron is added to the Cl atom(electron affinity) to form a chlorine ion is the same energy that would be required to remove the added electron from the ion to form an atom(electronegativity).
  • Here we find out that both energies are the same for the atom of Cl that is gaining electron and for the ion in which electron is being removed.

Learn more:

Ionization energy brainly.com/question/5880605

#learnwithBrainly

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A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon
ikadub [295]

<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q_1=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_1=675J/^oC\times 29.62^oC=19993.5J

To calculate the heat absorbed by water, we use the equation:

q_2=mc\Delta T

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J

Total heat absorbed = q_1+q_2

Total heat absorbed = [19993.5+114690.12]J=134683.62J=134.7kJ

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol

Hence, the enthalpy of the reaction is 269.4 kJ/mol

6 0
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Answer:

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