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xxMikexx [17]
3 years ago
7

a. Choose the best response for the following. The ionization energy for the chlorine atom is equal in magnitude to the electron

affinity for A) Cl- ion B) Cl+ ion C) F atom D) Cl atom E) none of these b. Choose the best explanation for this. A) The electron affinity can’t be determined without detecting the ionization energy. B) These energies are equal for all forms of the same element. C) Electron affinity doesn’t exist for these substances. D) Two particles participate in the same process, both energies being involved. Submit AnswerTry
Chemistry
1 answer:
Lunna [17]3 years ago
3 0

A) Cl- ion

B) These energies are equal for all forms of the same element

Explanation:

The ionization energy for a chlorine atom is equal in magnitude to the electron affinity of Cl⁻ ion because these energies are equal for all forms of the same element.

  • Electron affinity is the energy released  in adding an electron to  a neutral atom in the gas phase.
  • Ionization energy is the amount of energy required for the removal of an electron in atom or ion.
  • Here the energy released when an electron is added to the Cl atom(electron affinity) to form a chlorine ion is the same energy that would be required to remove the added electron from the ion to form an atom(electronegativity).
  • Here we find out that both energies are the same for the atom of Cl that is gaining electron and for the ion in which electron is being removed.

Learn more:

Ionization energy brainly.com/question/5880605

#learnwithBrainly

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3 years ago
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Could someone explain how they got this answer, explain step by step plz
gulaghasi [49]

Answer:

6.018 amu

Explanation:

Let 6–Li be isotope A.

Let 7–Li be isotope B.

Let the abundance of 6–Li be A%

Let the abundance of 7–Li be B%

The following data were obtained from the question:

Atomic mass of isotope A (6–Li) =.?

Atomic mass of isotope B (7–Li ) = 7.015 amu.

Abundance of 7–Li (B%) = 92.58%

Abundance of 6–Li (A%) = 100 – B% = 100 – 92.58 = 7.42%

Atomic mass of Lithium = 6.941amu

The atomic mass of isotope A (6–Li) can be obtained as follow:

Atomic mass = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

6.941 = [(mass of A x 7.42)/100] + [(7.015x92.58)/100]

6.941 = [(mass of A x 7.42)/100] + 6.494487

(mass of A x 7.42)/100 = 6.941 – 6.494487

(mass of A x 7.42)/100 = 0.446513

Mass of A x 7.42 = 100 x 0.446513

Mass of A x 7.42 = 44.6513

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Mass of A = 44.6513 / 7.42

Mass of A = 6.018 amu

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7 0
3 years ago
A chemist must dilute of aqueous aluminum chloride solution until the concentration falls to . He'll do this by adding distilled
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Answer:

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Explanation:

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Final molarity of the solution =75.0 \mathrm{mM}

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7 0
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What is a nonpolar covalent bond?
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