Answer:
Explanation:
The whole surface of hollow sphere = 4π r²
= 4 x 3.14 x (10 x 10⁻²)²
= 12.56 x 10⁻² m²
Area of the hole ( both side ) = 2 x π r²
= 2 x 3.14 x (10⁻³)²
= 6.28 x 10⁻⁶ m²
flux coming out of given charge at the centre as per Gauss's theorem
= q / ε₀ where q is charge at the centre and ε₀ is permittivity of the medium .
= 10 x 10⁻⁶ / 8.85 x 10⁻¹²
= 1.13 x 10⁶
This flux will pass through the surface of sphere so flux passing through per unit area
= 1.13 x 10⁶ / 12.56 x 10⁻²
= 8.99 x 10⁶ weber per m²
flux through area of hole
= 8.99 x 10⁶ x 6.28 x 10⁻⁶
= 56.45 weber .
