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Kay [80]
3 years ago
7

Give the number of particles of each element in NH3, ammonia.

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
3 0
You'll need Avogadro's number for this. NH3 has 1 Nitrogen and 2 Hydrogen. You'll multiply the molar mass of each times Avogadro's number. So:

molar mass N x 6.022x10^23 x 1 Nitrogen= total A

Molar mass H x 6.022x10^23 x 2 Hydrogen= total B

Add total A+B = your answer

I don't have a calculator or periodic table but if you plug in the numbers you'll get your answer. Hope it helps.
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Similarities and differences between covalent bonds and molecular interactions
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3 0
3 years ago
Select the correct image.<br> Which body part is vestigial in humans?
Dominik [7]

Answer:

should be appendix, I can't see any image tho.

8 0
2 years ago
Read 2 more answers
How many hydrogen's are in 6HCI
wolverine [178]

Answer:

6 atoms

Explanation:

In 6 moles of HCL (hydrochloric acid), there are 6 hydrogen atoms. Think about it this way: there is one hydrogen atom in HCL, or one hydrogen atom in one mole of HCL. Since there are 6 moles of HCL instead of one, this means there are six times as many hydrogen atoms. 6 times 1 is 6.

4 0
3 years ago
To cook a steak to medium-rare, it needs to have an internal temperature of 135
Nady [450]

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7 0
3 years ago
If 200. mL of 0.60 M MgCl2(aq) is added to 400 mL of distilled water, what is the concentration of Mg and Cl in the resulting so
sladkih [1.3K]

Answer:

C. 0.20 M Mg ion & 0.40 M Cl ion

Explanation:

MgCl₂ is a ionic salt which is dissociated as this

MgCl₂  →  Mg²⁺  +  2Cl⁻

First of all, we have a solution of 200 mL, with [MgCl₂] = 0.6M

Molarity . volume = moles.

0.6 mol/l . 0.2l = 0.12 mol

  MgCl₂  →  Mg²⁺  +  2Cl⁻

0.12mol      0.12         0.24

This moles are also in 400mL of water, so the new concentration is

[Mg²⁺] = 0.12 m/0.6L = 0.2M

[Cl⁻] = 0.24 m/0.6L = 0.4M

Remember we initially have 200mL and then, we add 400 mL, so we supose aditive volume. (600mL)

8 0
3 years ago
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