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KengaRu [80]
3 years ago
13

A body of mass 9 kg moves in a (counterclockwise) circular path of radius 8 meters, making one revolution every 8 seconds. You m

ay assume the circle is in the xy-plane, and so you may ignore the third component. A. Compute the centripetal force acting on the body.
Physics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

centripetal Force=44.36\ \rm N

Explanation:

<u>Given:</u>

Mass of the body m=9\ \rm kg

Radius of the circle R=8\ \rm m

Time period T=8\ \rm s

The centripetal Force acting on the body is given by F

F=\dfrac{4\pi^2 m R}{T^2}\\F=\dfrac{4\pi^2\times 9\times8}{8^2}\\F=44.36\ \rm N

Hence the centripetal force acting on the body is calculated

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A 2 kg mass is free falling in the negative Y direction when a 10 N force is exerted in the minus X direction. What is the accel
lara31 [8.8K]

Answer:

The mass's acceleration is 5 m/s^2 in the minus X direction and 9,8 m/s^2 in the minus Y direction.

Explanation:

By applying the second Newton's law in the X and Y direction we found that in the minus X direction an external force of 10 N is exerted, while in the minus Y direction the gravity acceleration is acting:

X-direction balance force: -10 [N] = m.ax

Y-direction balance force: -m*9,8 \frac{m}{s^2} = m.ay

Where ax and ay are the components of the respective acceleration and m is the mass. By solving for each acceleration:

ax=(-10 [N]) / m

ay=-m*9,8\frac{m}{s^2} / m

Note that for the second equation above the mass is cancelled and, the Y direction acceleration is minus the gravity acceleration:

ay=-9,8\frac{m}{s^2}

For the x component aceleration we must replace the Newton unit:

N =\frac{kg.m}{s^2}

ax= -10 \frac{kg.m}{s^2} / (2 kg)

ax= - 5 \frac{m}{s^2}

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3 years ago
the acceleration of a body in free fall depends on the place or the world in which it is, true or false?​
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The right answer is True

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Which of the following types of stars is the coolest? In Graph A, the curve peaks at 800 nm, in the red section of the visible l
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3 years ago
Read 2 more answers
1. A hydraulic lift is to be used to lift a truck masses 5000 kg. If the diameter of the
zheka24 [161]

Answer:

a)   F = 4.9 10⁴ N,  b)   F₁ = 122.5 N

Explanation:

To solve this problem we use that the pressure is transmitted throughout the entire fluid, being the same for the same height

1) pressure is defined by the relation

           P = F / A

to lift the weight of the truck the force of the piston must be equal to the weight of the truck

          ∑F = 0

          F-W = 0

          F = W = mg

          F = 5000 9.8

          F = 4.9 10⁴ N

the area of ​​the pisto is

          A = pi r²

          A = pi d² / 4

          A = pi 1 ^ 2/4

          A = 0.7854 m²

pressure is

          P = 4.9 104 / 0.7854

          P = 3.85 104 Pa

2) Let's find a point with the same height on the two pistons, the pressure is the same

          \frac{F_1}{A_1} = \frac{F_2}{A_2}

where subscript 1 is for the small piston and subscript 2 is for the large piston

          F₁ = \frac{A_1}{A_2} \ F_2

the force applied must be equal to the weight of the truck

          F₁ = ( \frac{d_1}{d_2} )^2\  m g

          F₁ = (0.05 / 1) ² 5000 9.8

          F₁ = 122.5 N

7 0
2 years ago
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