All categories

2 years ago

What type of charge is used as the test charge to determine the direction of electric fields?

Physics

1 answer:

Dmitriy789 [7]2 years ago

5 0

Answer:

B small positive charge

Explanation:

You might be interested in

Two identical light springs with spring constant k3 are now individually hung vertically from the ceiling and attached at each e

anyanavicka [17]

Answer:

Keq = 2k₃

Explanation:

We can solve this exercise using Newton's second one

F = m a

Where F is the eleatic force of the spring F = - k x

Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement

F + F = m a

k₃ x + k₃ x = m a

a = 2k₃ x / m

To find the effective force constant, suppose we change this spring to what creates the cuddly displacement

Keq = 2k₃

6 0

2 years ago

Place a small object on the number line below at the position marked zero. Draw a circle around the object. Mark the center of t

Viefleur [7K]

It’s is D bc it is and idk you should do it

6 0

3 years ago

Please need help ASAP. Would really appreciate it.

a_sh-v [17]

if i renember correctly its b

3 0

2 years ago

Resistance is a force that __________.

melisa1 [442]

The answer is slows objects down.

3 0

2 years ago

Read 2 more answers

Astronomers observe the motion of four planets that orbit a star similar to the Sun. Each planet follows an elliptical orbit aro

Sergeu [11.5K]

Answer:

planet that is farthest away is planet X

kepler's third law

Explanation:

For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets

T² = ( $\frac{4\pi ^2}{ G M_s}$ a³ = K_s a³

Let's apply this equation to our case

a = $\sqrt[3]{ \frac{T^2}{K_s} }$

for this particular exercise it is not necessary to reduce the period to seconds

Plant W

10² = K_s $a_{w}^3$

a_w = $\sqrt[3]{ \frac{100}{ K_s} }$

a_w = $\frac{1}{ \sqrt[3]{K_s} }$ 4.64

Planet X

a_x = $\sqrt[3]{ \frac{640^3}{K_s} }$

a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3

Planet Y

a_y = $\sqrt[3]{ \frac{80^2}{K_s} }$

a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6

Planet z

a_z = $\sqrt[3]{ \frac{270^2}{K_s} }$

a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8

From the previous results we see that planet that is farthest away is planet X

where we have used kepler's third law

3 0

3 years ago