Explanation:
Clearance:
For easy matching and dis matching of hole and shaft we use size of hole little bit more than the size of shaft and this difference in size is called clearance.
Backlash:
It is the clearance between the two mating gear to avoids failure of gears.Actually when temperature of gears increases then at the same time the size of gear also increases ,due this there is a possibility foe jamming of gears so to avoids this backlash is provides.
Interference:
When two gears are matting then addendum of one gear inters into the deddendum of another gear and due to this gears get jam .This phenomenon is called interference.
Answer: 12.4 feet
Explanation:
If there is a smooth transition and there is no change in slopes, energy considerations can be used
The cube has a kinetic energy of
ke = mv^2/2 = 10 lbm * 20^2ft^2/s^2 / 2 = 2000 lbm-ft^2 / s^2
At the highest point when there is a gain in potential energy
pe = mgh = 10 lbm * 32.2 ft/s^2 * h ft = 322 lbm ft^2/s^2
If there is no loss in energies,
pe = ke
322h lbm ft^2/s^2 = 2000 lbm ft^2/s^2
h = 2000 /322 = 6.211 (ft)
= h / sin(30) = 12.4 ft
Answer:
This is an asynchrnous 3-bit counter. Just note that this design is different and works differently than its synchronous counterpart. It's an easier design than its synchronous counterpart, and is not as reliable because it has delays.
Answer:
Q' = 8 KW.h
Q'=28800 KJ
Explanation:
Given that
Heat Q= 4 KW
time ,t = 2 hours
The amount of energy used in KWh given as
Q ' = Q x t
Q' = 4 x 2 KW.h
Q' = 8 KW.h
We know that
1 h = 60 min = 60 x 60 s = 3600 s
We know that W = 1 J/s
The amount of energy used in KJ given as
Q' = 8 x 3600 = 28800 KJ
Therefore
Q' = 8 KW.h
Q'=28800 KJ
Answer:
0 m/s , 3 m/s , 2 m/s^2
Explanation:
Given : s(t) = ( t^2 - 6t + 5)
v(t) = ds / dt = 2t - 6
s(0) = 5 m
s(6) = (6)^2 - 6*6 + 5 = 5 m
Vavg = ( s(6) - s(0) ) / 2 = 0 m\s
Find the turning point of particle:
ds/dt = 0 = 2t - 6
t = 3 sec
s(3) = 3^2 -6*3 + 5 = - 4
Total distance = 5 - (-4) + (5 - (-4)) = 18 m
Total time = 6s
Average speed = Total distance / Total time = 18 / 6 = 3 m/s
Taking derivative of v(t) to obtain a(t)
a (t) = dv(t) / dt = 2 m/s^2
