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Artemon [7]
3 years ago
11

H+ ions increase in concentration at lower pH values. Calculate how many more H+ ions there are in a solution at a pH = 2 than i

n a solution at a pH = 6. Find the concentration of H+ ions at a pH = 2 and at a pH = 6 in Table B. Then divide the concentration of H+ ions at a
pH = 2 by the of H+ ions at a pH = 6. Record your answer in Table C.

What is the concentration of H+ ions at a pH = 2?


mol/L

What is the concentration of H+ ions at a pH = 6?


mol/L

How many more H+ ions are there in a solution at a
pH = 2 than in a solution at a pH = 6?


need ASAP give
brainliest
Chemistry
2 answers:
joja [24]3 years ago
6 0

The H⁺ ion concentration can be calculated from pH values using the following equation:

pH=-log[H⁺]

1.) Given pH = 2

Using the above equation, 2 = - log [H⁺]

Therefore, [H⁺] = 10⁻² mol/L

2.) Given pH = 6

Using the same equation, we have 6 = - log [H⁺]

Hence, [H⁺] = 10⁻⁶ mol/L

3.) Taking the ratio of [H⁺] for pH = 2 and pH = 6, we have

\frac{10^{-2} }{10^{-6} } = 10⁴

So, there are 10,000 times more H⁺ ions in a solution of pH = 2 than that of pH = 6.

nalin [4]3 years ago
3 0

Answer:

0.01

0.000001

10,000

Explanation:

plz mark brainleist

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<h3>What is decomposition reaction?</h3>

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Mass_{reactant = Mass_{product}

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The question is incomplete. The complete question is :

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.

Solution :

Consider the equation of the reaction between NaOH and $HCl$

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If the volume of the $HCl$ taken = $V_1$ mL and the conc. of $HCl$ = $M_1$  mole/L

The volume of NaOH added up to the color change = $V_2 \text{  and conc of NaOH = M}_2$ mole/L

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or   when    $V_1M_1 = V_2M_2$

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$M_2$ is the molarity of NaOH added.

When both the NaOH and $HCl$ are of the same concentrations, i.e. if $M_1=M_2$, then $V_2=V_1$

Or the 40 mL of $HCl$ will need 40 mL of NaOH for a color change and

30 mL of $HCl$ would need 30 mL of NaOH for the color change (provided the concentration $M_1=M_2$)

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