What volume of a 6.67 m nacl solution contains 3.12 mol nacl??
2 answers:
If you are on ed. The answer is 0.468 L
The volume of a 6.67 m nacl solution
that contains 3.12 mol nacl is 0.468.
You just need to follow this formula:
C = n / V
So, it will be
V = n / C
<span> = 3.12 / 6.67 moles / Liter </span>
<span> = 0.468 L</span>
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