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astra-53 [7]
2 years ago
10

What volume of a 6.67 m nacl solution contains 3.12 mol nacl??

Chemistry
2 answers:
ioda2 years ago
8 0

If you are on ed. The answer is 0.468 L

natima [27]2 years ago
6 0

The volume of a 6.67 m nacl solution that contains 3.12 mol nacl is 0.468.

You just need to follow this formula:

C = n / V

So, it will be

V = n / C

<span>    = 3.12 / 6.67 moles / Liter </span>

<span>     = 0.468 L</span>

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Purification of nickel can be achieved by electrorefining nickel from an impure nickel anode onto a pure nickel cathode in an el
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Answer: 530 hours

Explanation:

The reduction of Nickel ions to nickel is shown as:

Ni^{2+}+2e^-\rightarrow Ni

96500\times 2=193000Coloumb of electricity deposits 1 mole of Nickel

1 mole of Nickel weighs = 58.7 g

Given quantity = 18.0 kg = 18000 g  (1kg=1000g)

58.7 g of Nickel is deposited by 193000 C of electricity

18000 g of Nickel is deposited by = \frac{193000}{58.7}\times 18000=59182282.8C of electricity

Q=I\times t

where Q= quantity of electricity in coloumbs  = 59182282.8C

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t= time in seconds = ?

59182282.8C=31.0A\times t

t=1909105.9sec

(1h=3600 sec)

t=530hours

Thus 530 hours are required to plate 18.0 kg of nickel onto the cathode if the current passed through the cell is held constant at 31.0 A

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