3 years ago

The temperature that sound moves through the air more quickly

Physics

1 answer:

Mademuasel [1]3 years ago

7 0

Sound moves faster in warmer temperature because the particles move faster

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False because faster moving slope would be going up and slower would be going down because its decreasing

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A child\'s top is held in place, upright on a frictionless surface. The axle has a radius of r = 2.96 mm. Two strings are wrappe

sladkih [1.3K]

Answer:

Explanation:

Given

radius r=2.96 mm

Tension T=2.4 N

time taken=0.74 s

Let $\alpha$ be the angular acceleration

$2 T\times r=I\times \alpha$

$2\times 2.4\times 2.96\times 10^{-3}=0.5\times m\times (2.96\times 10^{-3})^2\times \alpha$

$\alpha =\frac{4\times 2.4}{m\times 2.96\times 10^{-3}}$

$\alpha =\frac{3.24\times 10^3}{m} rad/s^2$

$\omega =\omega _0+\alpha \cdot t$

$\omega =0+\frac{3.24\times 10^3}{m}\times 0.74$

$\omega =\frac{2.4\times 10^3}{m} rad/s$

Angular momentum

$L=I\omega$

$L=0.5\times mr^2\times \omega$

$L=0.5\times m\times (2.96\times 10^{-3})^2\times \frac{2.4\times 10^3}{m}$

$L=0.01051 kg-m^2/s$

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3 years ago

You walk 45 m to the north, then turn 90° to your right and walk another 45 m How far are you from where you originally started?

docker41 [41]

C^2=a^2+b^2
c^2=45^2+45^2
c^2=4050
c=63.64
c=64
The answer is D.

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3 years ago

Which of the following correctly compares a scientific investigation to a demonstration

VikaD [51]

Without options I can simply compare a scientific investigation to a demonstration:

<span>An investigation is a process when you are answering a question about the answer of which you do not know while a demonstration is a display or show of how something happens, when you already know the outcome.
</span>

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A car travels at 40 km/hr for two hours and 55 km/hr for two hours. How far does the car travel? What is the average velocity?

KiRa [710]

Driving at 40 km/h for 2 h contributes a distance of 80 km, while driving at 55 km/h for 2h contributes 110 km, giving a total of 190 km traveled. If the car is traveling in the same direction throughout this ordeal, then the average velocity is

$\bar v=\dfrac{190\,\mathrm{km}}{4\,\mathrm h}=47.5\,\dfrac{\mathrm{km}}{\mathrm h}$

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3 years ago