We use the given data above to calculate the volume of gasoline that is being burned per minute by commercial airplanes.
Amount burned of 1 commercial airplane = <span>3.9 × 10³ ml of gasoline per second
Number of airplanes = </span><span>5.1 × 10³ airplanes
We calculate as follows:
</span> 3.9 × 10³ ml of gasoline per second / 1 airplane (5.1 × 10³ airplanes)(60 second / 1 min ) = <span>1.2 x 10^9 mL / min</span>
Answer:
expanding ends in the simplest form: 24p-36
Step-by-step explanation:
6x^2-x-2 this is of the form ax^2+bx+c
jk=ac=-12 and j+k=b=-1 so j and k must be -4 and 3 so
6x^2+3x-4x-2
3x(2x+1)-2(2x+1)
(3x-2)(2x+1)
Answer:
k=8
Step-by-step explanation:
2k+5=21 (-5 on both sides to get rid of +5)
2k=16 (divide by 2 to get rid of that 2 in front of K)
k=8
