414,104 easy =)
hopefully this helped
Answer:
21, 144, 12
Step-by-step explanation:
Given that a sample of 30 distance scores measured in yards has a mean of 7, a variance of 16, and a standard deviation of 4.
Let X be the distance in yard.
i.e. each entry of x is multiplied by 3.
New mean variance std devition would be
E(3x) = ![3E(x) = 21](https://tex.z-dn.net/?f=3E%28x%29%20%3D%2021)
Var (3x) = ![3^2 Var(x) = 9(16) =144](https://tex.z-dn.net/?f=3%5E2%20Var%28x%29%20%3D%209%2816%29%20%3D144)
Std dev (3x) = ![\sqrt{144 } =12](https://tex.z-dn.net/?f=%5Csqrt%7B144%20%7D%20%3D12)
Thus we find mean and std devition get multiplied by 3, variance is multiplied by 9
Step 1 distribute the 5 across (8+0.2)
6^3+5(8+0.2)
6^3+40+1
6^3+41 (<em>I simplified the +40 and the +1</em>)
Step 2 take 6 to the power of 3
6^3+41
6x6x6 6x6=36 36x6=216
216+41 (<em>Simplify!</em>)
257
I hope this helped!
Answer:
37.5
Step-by-step explanation: