Answer: b and c are the same so that leaves you with a and d I believe it's d not sure hope this helps ®:]©™
Explanation:
1) D
2) I would say A, but not 100%, its the only one that makes sense tho
M=energy transferred/ (temperature change*specific heat)
M= 5650/(26.6*1.0)
M=212g
Answer:
Given that
P = RT/V + a/V²
We know that
H= U + PV
For T= Constant (ΔU=0)
ΔH= ΔU +Δ( PV)
ΔH= Δ( PV)
P = RT/V + a/V²
P V= RT + a/V
dH/dV = d(RT + a/V)/dV
dH/dV = - a/V²
So the expression of dH/dV
![\dfrac{dH}{dV}=\dfrac{-a}{V^2}](https://tex.z-dn.net/?f=%5Cdfrac%7BdH%7D%7BdV%7D%3D%5Cdfrac%7B-a%7D%7BV%5E2%7D)
b)
In isothermal process
(ΔU=0)
Now by putting the all values
![\Delta H=nRT\ln{\dfrac{V_2}{V_1}}](https://tex.z-dn.net/?f=%5CDelta%20H%3DnRT%5Cln%7B%5Cdfrac%7BV_2%7D%7BV_1%7D%7D)
![\Delta H=1\times 0.08206\times 300\ln{\dfrac{40}{20}}](https://tex.z-dn.net/?f=%5CDelta%20H%3D1%5Ctimes%200.08206%5Ctimes%20300%5Cln%7B%5Cdfrac%7B40%7D%7B20%7D%7D)
ΔH = 17.06 L.atm
Answer:
He sees the light as 1c
Explanation:
According to relativity, the speed of light is the same in all inertial frame of reference.
If we were to add the velocities as applicable to a normal moving bodies, the relative speed of the light beam will exceed c which will break relativistic law since nothing can go past the speed of light.