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TEA [102]
3 years ago
11

A 7.4 A current is set up in a circuit for 7.8 min by a rechargeable battery with a 3.0 V emf. By how much is the chemical energ

y of the battery reduced?
Physics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:

10389.6 J

Explanation:

Power is the rate of doing work with respect to time, its S.I unit is in watts but it can also be expressed in J/s. Power is calculated using the formula:

Power=\frac{energy}{time}

Power is also the rate at which energy is used per second.

Energy is the capacity to do work and it is measured in joules (J).

Power = current × voltage = 7.4 A × 3 V = 22.2 W

Energy=power*time\\\\time=7.8\ min=7.8*60\ s=468\ s\\\\Energy=22.2*468\\\\Energy=10389.6\ J

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An airplane flies 1,592 miles east from phoenix, Arizona, to Atlanta, Georgia, in 3.68 hours. What is the average velocity of th
KiRa [710]

Answer:

433 mph

Explanation:

We know that

Velocity =\frac{Distance}{Time }...Eq(1)

Here,

Distance =1,592 miles

Time=3.68 hours

Putting the value of distance and Time in the Eq(1)  We get

Velocity =\frac{1592\ miles}{3.68\ hours}

Velocity = 432.608\  mph\\Velocity = 433 mph

therefore Average velocity is 433 mph

3 0
3 years ago
What happens to the particles of a liquid when energy is removed from them?
KonstantinChe [14]

Answer:

D: The distance between the particles decreases

Explanation:

Taking away energy slows down molecules, like how you slow down when you are cold (I think)

3 0
4 years ago
A baseball sits motionless near first base on a baseball diamond. What statement
Citrus2011 [14]

Answer:

B. There are no forces acting on the ball.

Explanation:

There are no forces acting on the ball.

5 0
3 years ago
A 4kg object has a momentum of 12 kg*m/s, what is the objects velocity?
Bezzdna [24]
Momentum = mass x velocity
12 = 4 x v | ÷ both sides by 4
12 ÷ 4 =v
v= 3 m/s
8 0
3 years ago
A test tube of length L and cross-sectional area A is submerged in water with the open end down so that the edge of the tube is
Margaret [11]

Answer:

if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

Explanation:

The air in the tube can be considered an ideal gas,

           P V = nR T

In that case we have the tube in the air where the pressure is P1 = P_atm, then we introduce the tube to the water to a depth H

For pressure the open end of the tube is

         P₂ = P_atm + ρ g H

Let's write the gas equation for the colon

            P₁ V₁ = P₂ V₂

            P_atm V₁ = (P_atm + ρ g H) V₂

             V₂ = V₁    P_atm / (P_atm + ρ g h)

If the air obeys Boyle's law e; volume within the had must decrease due to the increase in pressure, if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

The main assumption is that the temperature during the experiment does not change

6 0
3 years ago
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