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4 years ago

What wavelength of light would you report in units of nm, if the light had a wavelength of 7.60 x 10-10 m?

Physics

1 answer:

mezya [45]4 years ago

4 0

Explanation:

One meter is equal to $10^{9}nm$ , so:

$7.60*10^{-10}m*\frac{10^9nm}{1m}=0.76nm$

This wavelength does not correspond to any color of the visible spectrum. A wavelength of $0.76nm$ would correspond to soft X-rays, since these electromagnetic radiation have a wavelegth range from $1nm$ to $0.1nm$ .

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The 250 - turn primary coil of a step‑down transformer is connected to an AC line that is 120.0 V (rms). The secondary coil is t

KATRIN_1 [288]

Answer:

Number of turns in secondary is 20

Current in primary is 0.96 A

Explanation:

We have given number of turns in primary $N_p=250$

Voltage across primary of transformer $V_p=120volt$

Current in secondary coil $i_s=12A$

Voltage across secondary $V_s=9.6volt$

For transformer we know that $\frac{N_p}{N_s}=\frac{V_p}{V_s}$

So $\frac{250}{N_s}=\frac{120}{9.6}$

$N_p=20$

So number of turns in primary is 20

Now $\frac{N_p}{N_s}=\frac{i_s}{i_p}$

$\frac{250}{20}=\frac{12}{i_p}$

$i_p=0.96A$

Current in primary of transformer is 0.96 A

4 0

4 years ago

A car speeds past you sounding its horn at a frequency of 1000Hz. The frequency you hear:

ki77a [65]

Answer:

f' =1064.1025 Hz

Explanation:

We know that from doppler's effect

$f'=\frac{v+v_0}{v-v_s}f$

f'= observed frequency

f= actual frequency =1000 Hz

v= velocity of sound waves = 332 m/s

v_o= velocity of observer =0

v_s= velocity of source. ( let velocity of car be 20 m/s)

therefore,

$f'=\frac{332+0}{332-20}\times1000$

f' =1064.1025 Hz

3 0

3 years ago

What is the distance from axis about which a uniform, balsa-wood sphere will have the same moment of inertia as does a thin-wall

andrey2020 [161]

Answer:

$D_{s}$ ≈ 2.1 R

Explanation:

The moment of inertia of the bodies can be calculated by the equation

I = ∫ r² dm

For bodies with symmetry this tabulated, the moment of inertia of the center of mass

Sphere $Is_{cm}$ = 2/5 M R²

Spherical shell $Ic_{cm}$ = 2/3 M R²

The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass

I = $I_{cm}$ + M D²