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Masja [62]
3 years ago
10

When is a body said to be at rest

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

rest is the state of a body which is stationary relative to a particular frame of reference or another object.  When the state of a body does not changes with time with respect to its surroundings in a particular frame of reference that time  it is said to be at rest.

in other words we can say that when a body has zero velocity and its position is not changing with time relative to its surrounding then it is said to be at rest.

For example a chair on which you are sitting is at rest or a table on which your desktop is kept is rest because its position is not changing.

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Chemical properties of an acid include...
Cerrena [4.2K]

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2 years ago
The sound waves travel along this​
Anna35 [415]

Explanation:

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2 years ago
Given one mole of diamond vs one mole of graphite,
grandymaker [24]

Answer:

The pressure is P= -  6.39*10^8Pa

The temperature is T =1218.63 K

Explanation:

Generally Gibbs free energy is mathematically represented as

                   G = E + PV -TS

   Where  E is the enthalpy

               PV is the pressure volume energy (i.e PV energy)

                S  is the entropy

                T is the temperature

For stability to occur the Gibbs free energy must be equal to zero

Considering Diamond

  So at temperature of  T = 300 K

         E + PV - TS = 0

making P the subject

          P = \frac{TS-E}{V}

Now substituting 300 K for T , 2900 J  for E ,

                              3.42cm^3 = \frac{3.42}{1*10^6} = 3.42*10^{-6}m^3 for V and 2.38 J/K for S

     P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}

         P= -  6.39*10^8Pa

The negative sign signifies the direction of the pressure

Given that  P = 1*0^5Pa

making T the subject

            T = \frac{PV+E}{S}

Substituting into the equation

            T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}

                T =1218.63 K

             

         

7 0
3 years ago
Read 2 more answers
In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac
Elan Coil [88]

Answer:

a=0.284\ m/s^2

Explanation:

Given that,

Initially, the spaceship was at rest, u = 0

Final velocity of the spaceship, v = 11 m/s

Distance accelerated by the spaceship, d = 213 m

We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2

So, the acceleration experienced by the occupants of the spaceship is 0.284\ m/s^2.

5 0
3 years ago
Two flat conductors are placed with their inner faces separated by 8 mm. If the surface charge density on one of the inner faces
miskamm [114]

Answer:

= 0.0298V

Explanation:

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σ = 33pC/m²

= 33 × 10⁻¹²C/m²

ε₀ = 8.85 × 10 ⁻¹²C²/Nm²

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potential difference between two conductors = Ed

where d = 8mm = 8 × 10 ⁻³m

V = 3.7288 ×  8 × 10 ⁻³

   = 29.83 × 10 ⁻³

    = 0.0298V

4 0
3 years ago
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