The electric force on two charges, Q1 and Q2, that are separated by a distance d is given by F. if you increase their distance t
o 5d, what is the electric force?
1 answer:
Answer: F/ 25
Explanation: The electro static force between 2 charges follows an inverse square law.
F1×(d1)² = F2 × (d2)²
From the question, F1 =F, d1 =d and d2 = 5d, we are to find F2
F×d² = F2 × (5d)²
F×d² = F2 × 25d²
F2 = F × d²/25d²
F2 = F/ 25
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i think it looks good
yea it correct
BTW yw if it's right
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25000
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