How much energy is needed when 1.27 moles of sulfur reacts with excess
1 answer:
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Answer :
(1) The frequency of photon is,
(2) The energy of a single photon of this radiation is
(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol
Explanation : Given,
Wavelength of photon = (1 m = 100 cm)
(1) Now we have to calculate the frequency of photon.
Formula used :
where,
= frequency of photon
= wavelength of photon
c = speed of light =
Now put all the given values in the above formula, we get:
The frequency of photon is,
(2) Now we have to calculate the energy of photon.
Formula used :
where,
= frequency of photon
h = Planck's constant =
Now put all the given values in the above formula, we get:
The energy of a single photon of this radiation is
(3) Now we have to calculate the energy in J/mol.
The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol
Hello!
First, we need to determine the pKa of the base. It can be found applying the following equation:
Now, we can apply the Henderson-Hasselbach's equation in the following way:
![pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%20%5Cfrac%7B%5BCH_3NH_2%5D%7D%7B%5BCH_3NH_3Cl%5D%7D%20%29%3D10%2C65%2Blog%28%20%5Cfrac%7B0%2C18M%7D%7B0%2C73M%7D%20%29%3D10%2C04)
So, the pH of this buffer solution is 10,04
Have a nice day!
First, we need to determine the pKa of the base. It can be found applying the following equation:
Now, we can apply the Henderson-Hasselbach's equation in the following way:
So, the pH of this buffer solution is 10,04
Have a nice day!