Question

What expression gives the amount of light energy (in J per photon) that is converted to other forms between the fluorescence excitation and emission events?

Answer 1

Answer:

E = hf or $E=\dfrac{hc}{\lambda}$

Explanation:

The expression that gives the amount of light energy that is converted to other forms between the fluorescence excitation and emission events is given by :

E = hf

f is the frequency

$E=\dfrac{hc}{\lambda}$

c is the speed of light

$\lambda$ is the wavelength

Hence, this is the required solution.