Question

A volume of 5.0 L of air at 20°C is expelled from a container where it is instantly warmed to 50°C. Calculate the new volume that the air occupies at this temperature.

Answer 1

Answer: The new volume that the air occupies at this temperature is 5.5 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=5.0L\\T_1=20^oC=(20+273)K=293K\\V_2=?\\T_2=50^0C=(50+273)K=323K$

Putting values in above equation, we get:

$\frac{5.0}{293}=\frac{V_2}{323}\\\\V_2=5.5L$

Thus the new volume that the air occupies at this temperature is 5.5 L