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Elina [12.6K]
3 years ago
8

Ganymede, the largest of Jupiter’s moons,

Physics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:hereeee for pointssss only

Explanation:

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An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. the maximum speed of the o
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U= 1/2 * k * xmax^2

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7 0
3 years ago
A 190 N child is in a swing that is attached to ropes 2.10 m long. Find the gravitational potential energy of the child-Earth sy
Alekssandra [29.7K]

Answer:

a) Gravitational potential energy = 399 J

b) Gravitational potential energy = 66.5 J

c) Gravitational potential energy = 0 J

Explanation:

Hi there!

Please, see the attached figure for a better understanding of the problem.

a) When the ropes are horizontal, the height of the child, relative to the child's lowest position, is 2.10 m (see figure).

The gravitational potential energy is calculated as follows:

PE = mgh

Where:

PE = potential energy.

mg = weight of the child

h = height.

Then when the ropes are horizontal, the potential energy will be:

PE = 190 N · 2.10 m = 399 J

b) When the ropes make a 34.0° with the vertical, the height of the child is 2.10 m minus x (see figure). To find x, we can use trigonometry of right triangles:

cos angle = adjacent side / hypotenuse

cos 34.0° = x / 2.10 m

x = 2.10 m · cos 34.0° = 1.75 m

Then, the height of the child relative to the lowest position is

(2.10 m - 1.75 m) = 0.35 m

Therefore, the gravitational potential energy will be:

PE = 190 N · 0.35 m

PE = 66.5 J

c) When the child is at the bottom of the circular arc the height is zero (the child is at the lowest position), then, the gravitational potential energy will be zero.

6 0
3 years ago
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