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Answer:
Explanation:
Well use the combines gas law to evaluate this question;
P₁V₁/T₁ = P₂V₂/T₂ (Remember that at sea level the pressure is usually 1 atm)
1 * V₁ / 294.25 = 0.72 * V₂ / 277.95 (NB: Temperatures have to be in Kelvin)
V₁ / 294.25 * 277.95 = 0.72 V₂
0.945 V₁ = 0.72 V₂
0.945/0.72 V₁ = V₂
1.312 V₁ = V₂
The volume (V2) at 3000 m altitude will be <u>1.312 </u>bigger than the initial volume at sea level.
Using the ideal gas law equation, we can find the number of H₂ moles produced.
PV = nRT
Where P - pressure - 0.811 atm x 101 325 Pa/atm = 82 175 Pa
V - volume - 58.0 x 10⁻³ m³
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation,
82 175 Pa x 58.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 305 K
n = 1.88 mol
The balanced equation for the reaction is as follows;
CaH₂(s) + 2H₂O(l) --> Ca(OH)₂(aq) + 2H₂(g)
stoichiometry of CaH₂ to H₂ is 1:2
When 1.88 mol of H₂ is formed , number of CaH₂ moles reacted = 1.88/2 mol
therefore number of CaH₂ moles reacted = 0.94 mol
Mass of CaH₂ reacted - 0.94 mol x 42 g/mol = 39.48 g of CaH₂ are needed
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