Info: Al(oh)3 might be an improperly capitalized: Al(OH)3
Error: Some elements or groups in the reagents are not present in the products: O
Error: equation Al4C3+H2O=Al(oh)3+CH4 is an impossible reaction
Please correct your reaction or click on one of the suggestions below:
Al4C3 + H2O = Al(OH)3 + CH4
Answer:
Half will be green and half will be striped
Explanation:
Given green skin (G) is dominant to striped skin (g).
Cucumber 1 : Heterozygous (Gg)
Cucumber 2 : Homozygous striped (gg)
When Gg X gg :
G g
g Gg gg
g Gg gg
Half of the offspring will have Gg genotype so they will be green. Other half will have gg genotype so they will be striped.
Answer:
Rate = k [OCl] [I]
Explanation:
OCI+r → or +CI
Experiment [OCI] M I(-M) Rate (M/s)2
1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3
2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3
3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3
4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3
The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.
In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.
In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.
The rate law is given as;
Rate = k [OCl] [I]
I think it's 2:1 or 2:1:4. I mostly think it's 2:1 though. (:
Answer:
1. molarity is = 0.1174
2. molarity is = 9.3
3. molarity is =0.009392
Explanation:
Q#1.
mass of sucrose is 14.07g
molar mass of sucrose is 342 3g/mol
so, 14.07x1/342.3 = 0.0411
now the volume is of water is 0.35
so, 0.0411/0.35 = 0.1174
Q#2.
concentration is 4.5
so, 4.5x1/1000= 0.0045
then, 0.0411/0.0045 = 9.13
Q#3.
M1M1=M2M2
molarity of the same sucrose is 0.1174
so, diluted in 40mL
and the volumetric flask is 500mL
so, 0.1174x40/500= 0.009392