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4 years ago

Why a steel ship becomes magnetized as it is constructed?

2 answers:

3 0

<em>iron or steel is only magnetized when current is passed through it...
ship is magnetized because <u></u>it has a superstructure,, during welding of ship enormous amount of current is passed through it and also it goes on and on path through the whole structure which aggregates the current up to thousands of amperes ,,,
as a result this current re aline all the molecules because of which they become a little magnetic and make the entire steel ship magnetic :)</em>

tensa zangetsu [6.8K]4 years ago

3 0

Answer:

Because steel is a ferromagnetic substance.

Explanation:

A ship is build from number of plates joined together as a group of panels and block by welding.

A huge amount of welding is done for the construction of ships. During this a high ampere of current is required. As steel is a ferromagnetic substance, it has magnetic dipoles which tends to acquire magnetic behavior once being passed through electric current.

Hence when huge amount of current is passed through steel plates for the formation of ship, it becomes magnetized.

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A rectangular loop with dimensions 4.20 cm by 9.50 cm carries current I. The current in the loop produces a magnetic field at th

rusak2 [61]

Answer:

1.63 A and in clockwise direction

Explanation:

The magnetic field due to the rectangular loop is :

$B=\frac{2 \mu_0 I}{\pi}\left(\frac{\sqrt{L^2+W^2}}{LW}\right)$

Given : W = 4.20 cm

$=4.20 \times 10^{-2} \ m$

L = 9.50 cm

$= 9.50 \times 10^{-2} \ m$

$B = 3.40 \times 10^{-5} \ T$

Rearranging the above equation, we get

$I=\frac{B \pi LW}{2 \mu_0\sqrt{L^2+W^2}}$

$I=\frac{(3.40 \times 10^{-5}) \pi(9.50 \times 10^{-2})(4.20 \times 10^{-2})}{2(4 \pi \times 10^{-7})\sqrt{(9.50 \times 10^{-2})^2+(4.20 \times 10^{-2})^2}}$

I = 1.63 A

So the magnitude of the current in the rectangular loop is 1.63 A.

And the direction of current is clockwise.

4 0

3 years ago

. When using straight ladders, the base of the ladder should be _____ away from the wall or other vertical surface for every ___

guapka [62]

one foot; four feet is the answer

3 0

3 years ago

Read 2 more answers

You throw a softball (of mass 300 g) straight up into the air. It reaches a maximum altitude of 10.1 m and then returns to you.

Marysya12 [62]

Answer

given,

mass of the ball = 300 g

= 0.3 Kg

maximum altitude of the ball = 10.1 m

Potential energy of the softball:

PE = m g h

PE = 0.3 x 9.8 x 10.1

PE = 29.69 J

Maximum kinetic energy at which the ball is released from hand to reach height of 10.1 m is 29.69 J.

Kinetic energy at which ball returns to your hand is equal to 29.69 J.

speed of the ball

$KE=\dfrac{1}{2}mv^2$

$29.69=\dfrac{1}{2}\times 0.3 \times v^2$

v² = 197.93

v = 14.069 m/s

6 0

4 years ago

The radioactive element radium (Ra) decays by a process known asalpha decay,in which the nucleus emits a helium nucleus. (Factoi

tamaranim1 [39]

<u>Answer:</u> The energy released in the decay process is $4.6800\times 10^{11}J$

<u>Explanation:</u>

The equation for the alpha decay of Ra-226 follows:

$_{88}^{226}\textrm{Ra}\rightarrow _{2}^{4}\textrm{He}+_{86}^{222}\textrm{Rn}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Rn}+m_{He})-(m_{Ra})$

We know that:

$m_{Rn}=222.0176u\\m_{Ra}=226.0254u\\m_{He}=4.0026u$

Putting values in above equation, we get:

$\Delta m=(222.0176+4.0026)-(226.0254)=-0.0052g=-5.2\times 10^{-6}kg$

(Conversion factor: 1 kg = 1000 g )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(-5.2\times 10^{-6}kg)\times (3\times 10^8m/s)^2$

$E=-4.6800\times 10^{11}J$

Hence, the energy released in the decay process is $4.6800\times 10^{11}J$

8 0

3 years ago

Explain the differences between horticulture and agriculture.

sammy [17]

<h2><u>Hello </u><u>There</u></h2>

$\tt{Difference \: Between \: \underline\red {Horticulture} \: And \: \underline\green{Agriculture}}$

$\text{\underline\red {Horticulture}}$

The Cultivation of Fruits, Vegetables and Flowers for domestic and international markets are called Horticulture.

$\text{\underline\green{Agriculture}}$

It is science, art and occupation of cultivating the soil, producing crops and livestock. It is systematic and controlled use of living organisms and the environment to improve the human condition.

<h3>Hope This Helps</h3>

6 0

2 years ago