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BARSIC [14]
2 years ago
11

- Una carga de -5x10-6 C está situada a 20cm delante de otra

Physics
1 answer:
saul85 [17]2 years ago
3 0

Answer:

F = 5.625\,N (Fuerza de repulsión/Repulsive force)

Explanation:

La fuerza ejercida entre las dos partículas se calcula por la Ley de Coulomb (The force exerted between the two particles is determined by Coulomb's Law):

F = k \cdot \frac{q_{1}\cdot q_{2}}{r^{2}}

Donde (Where):

k - Constante electrostática, medido en \frac{N\cdot m^{2}}{C^{2}} (Electrostatic constant, measured in \frac{N\cdot m^{2}}{C^{2}}).

q_{1}, q_{2} - Magnitudes de las cargas de cada partícula, medidos en Coulombs. (Magnitudes of charges from each particle, measured in Coulombs).

r - Distancia entre las partículas, medida en metros.

La fuerza electrostática es (Electrostatic force is):

F = \left(9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot \frac{(5\times 10^{-6}\,C)\cdot (5\times 10^{-6}\,C)}{(0.20\,m)^{2}}

F = 5.625\,N

Dado que las partículas tienen el mismo signo de carga, la fuerza es de repulsión. (Given that both particles have the same charge sign, the force is of repulsive nature)

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