Answer : To find the molar mass of unknown gas we need to solve the equation of rate of diffusion and molecular weight of the gases, which is as follows;
here the mol wt of gas B is not known so we take it as '<em>x'
</em>on solving we get 7 X
/ 4.9 X
<em>
</em>mol. wt of unknown gas =
20.0 g
Answer:
a. 1,157x10⁻⁵M/s
b. 5,787x10⁻⁶M/s
Explanation:
For the reaction:
2H₂O₂(aq) → 2H₂O(l) + O₂(g).
a. The rate law of descomposition is:
Where d[H₂O₂] is the change in concentration of H₂O₂ (between 0s and 2,16x10⁴s) is (1,000M-0,500M) and dt is (0s-2,16x10^4s). Replacing:
As this rate is = d[O₂]/dt(Rate of production of O₂), the rate of production of O₂(g) is <em>1,157x10⁻⁵M/s</em>
b. Between 2,16x10⁴s and 4,32x10⁴s, rate law is:
The rates are <em>5,787x10⁻⁶M/s</em>
I hope it helps!
Answer:
m/s
Explanation:
One 'm' and one 's' in the numerator and the denominator 'cancel out' and you are left with m / s
The answer to this question is Option 3- Na2O
Answer:
Sodium has one valence electron. Valence electrons are electrons found in the outermost shell of an atom. The shell number representing the valence shell will differ depending on the atom in question. For sodium, which is in the 3rd row of the periodic table, the valence electrons will be found in the 3rd shell.