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Flura [38]
3 years ago
11

What is the measurement 1042 L rounded off to two signicant digits ?

Chemistry
1 answer:
SOVA2 [1]3 years ago
5 0
This is a really hard question. Because if you change it to 1,000 then that's only one. If you add the decimal so it's 1,000. , then that's 4 if you change it to 1,040, that's 3. So you can not change that to 2 significant digits.
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alexandr402 [8]
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8 0
3 years ago
The second reaction in the formation of sulfuric acid occurs slowly.
rjkz [21]

<u>Answer:</u> The correct option is NO_2(g)

<u>Explanation:</u>

A catalyst is defined as the chemical species that increases the reaction rate but does not participate in it and is left behind after the completion.

A homogeneous catalyst is one that is present in the same phase as the reactants and products.

A heterogeneous catalyst is one that is present in different phase as that of reactants and products.

For the given chemical reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

As all the reactants and products are in gaseous state so, the homogeneous catalyst must also be in the gaseous state only.

Hence, the correct option is NO_2(g)

5 0
2 years ago
Describe the characteristics that identify a sample of matter as being a substance.
ollegr [7]

No matter how big or little a material is, its properties remain the same. Size, form, color, and mass are the qualities that distinguish a material from non-substances. All of these qualities, including size, shape, color, and mass, can be seen and measured. Some characteristics are physical, while others are chemical. Physical characteristics include mass, volume, density, and color.  Viscosity and solubility are examples of chemical qualities.

6 0
2 years ago
375 mL of a 0.88 M potassium hydroxide solution is added to 496 mL of a 0.76 M cesium hydroxide solution. Calculate the pOH of t
AysviL [449]

Answer:

pOH of resulting solution is 0.086

Explanation:

KOH and CsOH are monoacidic strong base

Number of moles of OH^{-} in 375 mL of 0.88 M of KOH = \frac{0.88\times 375}{1000}moles = 0.33 moles

Number of moles of OH^{-} in 496 mL of 0.76 M of CsOH = \frac{0.76\times 496}{1000}moles = 0.38 moles

Total volume of mixture = (375 + 496) mL = 871 mL

Total number of moles of OH^{-} in mixture = (0.33 + 0.38) moles = 0.71 moles

So, concentration of OH^{-} in mixture, [OH^{-}] = \frac{0.71}{871}\times 1000M=0.82M

Hence, pOH=-log[OH^{-}]=-log(0.82)=0.086

8 0
3 years ago
Hii can someone help me pls this is the last question
lara31 [8.8K]

Answer:

B. 126

Explanation:

the scale is 1 to 42 so the scale would be:

3 cm:x cm

3 * 42 = 126 cm

8 0
2 years ago
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